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EleoNora [17]
3 years ago
7

In circle o, mZWBY = 72°.

Mathematics
1 answer:
likoan [24]3 years ago
7 0

Answer:

Answer is B. 36 degrees

Step-by-step explanation:

From the diagram,

angle WBY = 2 × angle WXY

angle WBY = 72°

angle WXY =

\frac{angle \: WBY}{2}

=  \frac{72}{2}

= 36 \: degrees

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Hey there please help me with this question
olga_2 [115]

Answer:

see explanation

Step-by-step explanation:

sum the parts of the ratio, 2 + 1 = 3 parts , thus

81 cm² ÷ 3 = 27 cm² ← value of 1 part of the ratio

2 parts = 2 × 27 = 54 cm²

Area of A = 54 cm² and area of B = 27 cm²

The side of the original square = \sqrt{81} = 9 cm

The width of both rectangles is 9 cm ( width remains unchanged after cut )

Thus

Rectangle A

9 × length = 54 ( divide both sides by 9 )

length = 6 cm

Rectangle B

9 × length = 27 ( divide both sides by 9 )

length = 3 cm

Rectangle A → length = 6 cm, width = 9 cm

Rectangle B → length = 3 cm , width = 9 cm

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Step-by-step explanation:

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Find the perimeter of this triangle ????
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Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola
Artist 52 [7]

Answer:

Tomas added 6 to both sides of the equation instead of subtracting 6.

Step-by-step explanation:

Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola that costs $2.00 per pound. The walnuts cost $6 per pound. He uses the equation 2x + 6y = 12 to represent the total cost, where x represents the number of pounds of granola and y represents the number of pounds of walnuts. He solves the equation for y, the number of pounds of walnuts he can buy.

Given:

2x + 6y = 12

where

x = number of pounds of granola y = number of pounds of walnuts

The correct solution to the problem

x = 3 pounds

2x + 6y = 12

2(3) + 6y = 12

6 + 6y = 12

Subtract 6 from both sides

6 + 6y - 6 = 12 - 6

6y = 6

Divide both sides by 6

y = 6/6

= 1

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Tomas added 6 to both sides of the equation instead of subtracting 6.

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