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Rama09 [41]
3 years ago
6

A college basketball coach has 12 players on his team. eight players are receiving scholarships, and four are not. the coach dec

ides to select a starting lineup by selecting five names out of a bowl. the probability that 4 of 5 players selected are on scholarship is _____. record answer to three decimal places
Mathematics
1 answer:
EleoNora [17]3 years ago
5 0

Solution: The given problem is a binomial distribution.

The probability that a team member receives a scholarship is \frac{8}{12} = 0.67

Therefore, the given problem follows binomial with n = 5 and p = 0.6667

Now the probability that 4 of 5 players selected are on scholarship is:

P(x=4) = \binom{5}{4} \times 0.6667^{4} (1-0.6667)^{5-4}

                  =5 \times 0.1976 \times 0.3333

                  =0.329

Therefore, the probability that 4 of 5 players selected are on scholarship is 0.329

                 

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Write an equation to solve each problem and then solve it. b In a 3-digit number, the hundreds digit is four more than the ones
Misha Larkins [42]

Answer:

digits are: 0, 4, 8. The required number is: 480.

Step-by-step explanation:

→ Let ones digits is 'x', then according to the condition the hundreds digit is 'x+4', and the tens digit is '2(x+4)'.

→ According to the condition the sum of the digits is: x+(x+4)+2(x+4)=12.

→ After evaluation this equation, x=0 - this is ones digit;

→ x+4=0+4=4 - this is hundreds digit;

→ 2(x+4)=2(0+4)=8 - this is ten digit.

3 0
3 years ago
-2/x^2-4 + x-1/x^2-2x
Fiesta28 [93]

Answer:

I need help with this too

Step-by-step explanation:

8 0
3 years ago
Find the indefinite integral. (Use C for the constant of integration.)
mart [117]

Answer:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

tep-by-step explanation:

In order to find the integral:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx

we can do the following substitution:

Let's call

u=(x^3-x^2+x)

Then

du = (3x^2-2x+1) dx

which allows us to do convert the original integral into a much simpler one of easy solution:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx  = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C

Therefore, our integral written in terms of "x" would be:

\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C

7 0
2 years ago
Can someone please help me with 21-24 and explain/ show how you got the answer?
oksano4ka [1.4K]
The solution (x,y) needs to work in both equations. With multiple choice you can do guess and test method. Otherwise you need to combine the two equations into one by substitution or elimination methods.

21. substitution works well here since one equation is y= x+3. you can easily substitute the (x+3) for y in the other equation.
2x + (x+3) = -6
3x + 3 = -6
3x = -9
x = -3
use this in either equation to find y.
y = (-3)+3
solution: (-3,0)

22. these both equal y so they equal each other.
4x - 1 = 3x +6
4x - 3x = 6 + 1
x = 7
use this in either equation to find y
y = 4(7) - 1
y = 28 - 1
y = 27
solution: (7,27)

23. one equation is y = 2x - 3. So substitute (2x -3) for y in the other equation.
4x = 2(2x - 3) + 6
4x = 4x - 6 + 6
4x = 4x
x = x
any solution will work, infinitely many.

24. infinitely many solutions means the two equations are the same equation. Like the previous one they didn't look the same but if you put them both in terms of y...
y= 2x-3
4x = 2y + 6
4x - 6 = 2y
(4x - 6)/2 = y
2x - 3 = y
same equation.

from the image, I can't see all options but A & C do not look like the same equations. It's got to be either B or D.

3 0
3 years ago
Is 84 / 56 = 16 / 9 proportional
nydimaria [60]

Answer:

No

Step-by-step explanation:

84/56=1.5

16/9=1.78

     

6 0
2 years ago
Read 2 more answers
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