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ArbitrLikvidat [17]
2 years ago
14

There were 11 students running in a race how many different arrangements of first second and third place are possible

Mathematics
1 answer:
notka56 [123]2 years ago
3 0

<u>Answer:</u>

<h2>990</h2>

<u>Explanation:</u>

For first place, we have 11 choices

11 × __ × __

For second place, we have 10 choices

11 × 10 × __

And for third place, we have 9 choices

11 x 10 x 9 = 990 ways

This is also a permutation

11! / (11-3)! = 990

Hope it helps

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