There were 11 students running in a race how many different arrangements of first second and third place are possible
1 answer:
<u>Answer:</u>
<h2>990</h2>
<u>Explanation:</u>
For first place, we have 11 choices
11 × __ × __
For second place, we have 10 choices
11 × 10 × __
And for third place, we have 9 choices
11 x 10 x 9 = 990 ways
This is also a permutation
11! / (11-3)! = 990
Hope it helps
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Sorry wish I could help but I need to see the picture to answer the question. Sorry :-(
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It’s C mate! Hope this helps! :))
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