If my explanation doesn't make sense, there are some pretty good utube videos about it.
Here is our equation: 3x + 2y = 5
At the y-intercept (the point where the line meets y on a graph), x=0. The same can be applied to the x-intercept, as y=0. So, to find each intercept, we can treat 3x + 2y = 5, as we would with any other equation.
First, we will find the y-intercept. We know x=0, so that can be plugged in: 3(0) + 2y = 5
Anything times 0 is 0.
2y = 5
Divide both sides by 2 to isolate y:
y = 5/2 (or 2.5)
The y intercept is 5/2 (or 2.5).
Now, do the same for x, given that y=0: 3x + 2(0) = 5
Anything times 0 is 0.
3x = 5
Divide both sides by 3 to isolate x:
x = 5/3 (or 1.7
The x intercepts is 5/3 (or 1.7)
(You should probably use the fractional versions of the answers, but it depends on your teacher, I suppose)
Let me know if you have any questions about this! :)
Answer:

Step-by-step explanation:
Since you want to get q only and q appears in both side of the equation. Try to isolate q to one side.
1) Expand 2(q+p)
2q + 2p = 1 + 5q
2) Move all q terms to one side
5q - 2q = 2p - 1
3q = 2p - 1
3) Divide 3 on both side (to isolate q)
q = 
30 degrees because it's a 30-60-90
Let the width be x cm.
Then length=3x-4 cm.
Its perimeter is 64 cm.
We know that perimeter of a rectangle= 2(length+width)
So,
2(3x-4+x)=64
6x-8+2x=64
6x+2x=64+8
8x=72
x=9
Therefore,
length=(3×9-4)cm=(27-4)cm=23 cm.
Width=9 cm.