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solong [7]
3 years ago
5

What are the solutions of the quadratic equation? 2 x^2 – 16 x + 32 = 0

Mathematics
1 answer:
White raven [17]3 years ago
3 0

Answer:

X=4,4

Step-by-step explanation:

2 x^2 – 16 x + 32 = 0

2(x^2-8x+16)=0

X^2-(4+4)X+16=0

x^2-4x-4x+16=0

x(x-4)-4(x-4)=0

(x-4)(x-4)=0

X=4,4

So the solution is X=4,4

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3 years ago
A restaurant operator in Accra has found out that during the partial lockdown, if she sells a plate of her food for GH¢20 each,
Lilit [14]

Answer:

Step-by-step explanation:

First, note this parameters from the question.

We let x = number of $5 increases and number of 10 decreases in plates sold.

Our Revenue equation is:

R(x) = (300-10x)(10+5x)

We expand the above equation into a quadratic equation by multiplying each bracket:

R(x) = 3000 + 1500x - 3000x - 1500x^2

R(x) = -1500x^2 - 1500x + 3000 (collect like terms)

Next we simplify, by dividing through by -1500

= 1500x^2/1500 - 1500x/1500 + 3000/1500

= X^2 - x + 2

X^2 - x + 2 = 0

Next, we find the axis of symmetry using the formula x = -b/(2*a) where b = 1, a = 1

X = - (-1)/2*1

X = 1/2

Number of $5 increases = $5x1/2 = $2.5

=$2.5 + $20 = $22.5 ticket price gives max revenue.

7 0
3 years ago
Why will percent of change always be represented by a positive number?
Murljashka [212]
Percent of change will always be positive because the change is an absolute value. As we know, absolute value is always a positive value because you don't pay attention to the direction, only the distance is important. 
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3 years ago
Find the domain of the graphed function.
attashe74 [19]

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Step-by-step explanation:

7 0
3 years ago
A reflecting pool is shaped like a right triangle with one leg along the wall of a building. the hypotenuse is 9 feet longer tha
morpeh [17]

Answer:

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

Step-by-step explanation:

In the question, the shape of the pool is right triangle.

Let the leg side along the wall to be the x ft

Let the other leg side  to be 7+x ft

Let the longest side/hypotenuse to be x+9 ft

Apply the Pythagorean relationship where the sum of squares of the legs equals the square of the hypotenuse

This means;

x^2 +(x+7)^2=(x+9)^2\\\\

Expand the terms in brackets

x^2+(x+7)^2=(x+9)^2\\\\\\x^2+x^2+14x+49=x^2+18x+81

collect like terms

x^2+x^2-x^2=18x-14x+81-49\\\\\\x^2=4x+32\\\\\\x^2-4x-32=0

solve for x in the quadratic equation by factorization

x^2-4x-32=0\\\\\\x^2-8x+4x-32=0\\\\\\x(x-8)+4(x-8)=0\\\\\\(x+4)(x-8)=0\\\\\\x+4=0,x=-4\\\\x-8=0,x=8

Taking the positive value of x;

x=8ft

Finding the lengths

Leg side along the wall = x ft = 8 ft

The other leg side = 7+x ft = 7+8=15 ft

The Hypotenuse =9+x ft = 9+8 = 17 ft

6 0
3 years ago
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