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3 years ago

15

Graph the function f(x)=(x-3)^2+2f(x)=(x−

lt="3)^{2}" align="absmiddle" class="latex-formula">+2

1 answer:

charle [14.2K]3 years ago

8 0

I believe that’s what your asking for
Sorry if it doesn’t help

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Which answers are equal to the expression below? Check all that apply.

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B and D.

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4 years ago

5. Which of the following linear functions has a graph which passes through points (−5,−2) and (−3,0)?

sergeinik [125]

Answer:

$f(x) = x + 3$

Step-by-step explanation:

Given

Points (−5,−2) and (−3,0)

Required

Find a linear function that passes through the given points

The question implies that we solve for the equation for the line;

First, the slope of the line must be calculated;

This is calculated as thus:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where $(x_1,y_1) = (-5,-2)\ and\ (x_2,y_2) = (-3,0)$

So, $m = \frac{y_2 - y_1}{x_2 - x_1}$ becomes

$m = \frac{0 - (-2)}{-3 - (-5)}$

$m = \frac{0 + 2}{-3 + 5}$

$m = \frac{2}{2}$

$m = 1$

The equation of the line can then be calculated using any of the given points;

Using

$m = \frac{y - y_1}{x - x_1}$

$Where\ (x_1,y_1) = (-5,-2)\ and\ m =1$

We have

$1 = \frac{y-(-2)}{x-(-5)}$

$1 = \frac{y+2}{x+5}$

Multiply both sides by x + 5

$(x+5)*1 = \frac{y+2}{x+5} * (x+5)$

$x + 5 = y + 2$

Subtract 2 from both sides

$x + 5 - 2 = y + 2 - 2$

$x + 3 = y$

$y = x + 3$

Replace y with f(x)

$f(x) = x + 3$

Hence, from the list of given options; Option B is correct

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