Answer:
-9, 15
Step-by-step explanation:
Subtract 7 and multiply by 4
1/4 |2x-6| +7 = 13
1/4 |2x -6| = 6
|2x -6| = 24
2x -6 = ± 24
2x = 6 ±24
x = 3 ±12
x = -9, 15
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For graphing purposes, it is often convenient to rewrite the equation so the solutions are where the function is zero. Here, we can do that by subtracting 13 from the equation.
(1/4 |2x -6| +7) -13 = 0
Answer:
Explanation:
The image attached has the mentioned <em>histogram</em>.
Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.
Only the rectangle for the class [3,4] is missing.
The height of each rectangle is the relative frequency of the corresponding class.
The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.
In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.
<u>1. Sum of the known relative frequencies</u>:
<u>2. Missing frequency</u>:
<u>3. Conclusion</u>:
Answer:
20 students should be on each float
Step-by-step explanation:
Number of seniors = 100
Number of juniors = 80
To find number of students that should be on each float, find highest common factor (H.C.F) of 100 and 80
Write prime factorisation of 100 and 80.
100 = ×
80 = × 5
So,
H.C.F(100, 80) = × 5 = 4 × 5 = 20
Therefore,
20 students should be on each float