All categories

2 years ago

What is the median of 90,30,20,30,60,30,80

Mathematics

2 answers:

Harrizon [31]2 years ago

6 0

Answer:

The median is 30.

Step-by-step explanation:

To find the median, you must first list all numbers from least to greatest.

In this case, we get 20, 30, 30, 30, 60, 80, 90.

Median is the middle number in the group. Here, we can clearly see that 30 is the middle number.

Keep in mind that if a group doesn't have a middle number, a.k.a. even number of numbers, take the 2 middle numbers, add them, then divide the sum by 2 to get the median.

MariettaO [177]2 years ago

4 0

Answer:

you have an odd number, divide by 2 and round up to get the position of the median number.

Step-by-step explanation:

you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

You might be interested in

0.75(3.55a - 6b) simplified please

GREYUIT [131]

Answer:

Step-by-step explanation:

2.66a-6b

3 0

3 years ago

6n + 9 = -3 - 21 - 6

denis23 [38]

$6n+9=-3-21-6$
subtract the numbers: $-3-21-6=-30$
$6n+9=-30$
subtract 9 from both sides
$6n+9-9=-30-9$
simplify
$6n=-39$
divide both sides by 6
$\frac{6n}{6}= \frac{-39}{6}$
$n= \frac{-13}{6}$
decimal $n=-6.5$
Hope this helps :)

3 0

2 years ago

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0

2 years ago

17. Admission prices to Cinema I to see a movie are $9.50 for an adult and $6.50 for a child. The admission charge at Cinema II

maksim [4K]

Answer:

a. 9.5x + 6.5(x+c) < 8 when c>0

b. Must be one child more than the no. of adults.

Step-by-step explanation:

For Cinema 1:

for adult = $9.50

for child = $6.50

For Cinema 2:

Per person regardless of age = $8.00

First of all, we will find out the condition when per person rates in both cinema are equal.

Assume x = no. of adults

y = no. of children

Rate per person in Cinema I = Rate per person in Cinema II

(9.5x + 6.5y)/(x+y) = 8

9.5x + 6.5y = 8(x+y)

9.5x + 6.5y = 8x + 8y

9.5x-8x = 8y-6.5y

=> x = y

So rates are equal when no. of adults equals no. of children

For Cinema I to have better rates, no. of children should be atleast 1 more than the no. of adult. In this way the rate per person of Cinema I will be less than 8

Hence we form an inequality when y = x+c and c > 0

9.5x + 6.5(x+c) < 8 when c>0

Hence there must be 1 more children than the no. of adults attending Cinema I for it to be a better deal.

4 0

2 years ago

Read 2 more answers

For what interval(s) is the function negative?

serious [3.7K]

Answer:

The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero). y-values that are on the x-axis are neither positive nor negative. The x-axis is where y = 0.

Step-by-step explanation:

7 0

2 years ago