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BigorU [14]
3 years ago
14

The sum of a number and 5 is squared. The result is 81.

Mathematics
1 answer:
lianna [129]3 years ago
5 0

Answer:

x=4, x=-14

Step-by-step explanation:

With a radical

(x+5)^2=81

\sqrt{(x+5)^2} =\sqrt{81}

x+5=9

x=4

x+5=-9

x=-14

Hope it helped :)

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8214 divided by 173 with a remainder in a simple form
wolverine [178]
47 R83  
^^^^^^^^^^^^^^^^^^^^                                             


4 0
4 years ago
A school is arranging a field trip to the zoo. The school spends 696.96 dollars on passes for 40 students and 4 teachers. The sc
Deffense [45]

$25.27 were spent on a pass and lunch for each student.

Step-by-step explanation:

Total students = 40

Teachers = 4

Amount spent on passes for students and teachers = $696.96

Amount spent on one pass = \frac{Total\ amount\ spent}{No.\ of\ students\ and\ teachers}

Amount spent on one pass = \frac{696.96}{40+4}=\frac{696.96}{44}

Amount spent on one pass = \$15.84

Amount spent of students' lunches = $377.20

Amount spent on one lunch = \frac{Total\ amount\ spent\ on\ lunches}{No.\ of\ students}

Amount spent on one lunch = \frac{377.20}{40} = \$9.43

Total spent on each student = Amount of one pass + amount of one lunch

Total\ spent\ on\ each\ student= 15.84+9.43 = \$25.27

$25.27 were spent on a pass and lunch for each student.

Keywords: division, addition

Learn more about addition at:

  • brainly.com/question/11416224
  • brainly.com/question/11638377

#LearnwithBrainly

3 0
3 years ago
A triangle can contain 1 or less obtuse angles Indirect proof
son4ous [18]

Answer:

Well, if we know that an obtuse angle is an angle greater than 90 degrees, and that a triangle's angles MUST sum up to 180 degrees and contain three angles. Then it logically follows that there's no way for a triangle to have 3 angles AND have two of the three be greater than or equal to 90 degrees as the remaining angle would have to be zero degrees or some "negative angle"- which I am pretty sure doesn't exist lol! As for a proof, I think you can cook up something with what I have given you so far :)

7 0
3 years ago
Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet,"
Bas_tet [7]

The question is:

Let l(x) be the statement "x has an Internet connection" and C(x, y) be the statement "x and y have chatted over the Internet," where the domain for the variables x and y consists of all students in your class. Use quantifiers to express each of these statements.

a. Jerry does not have an Internet connection.

b. Rachel has not chatted over the Internet with Chelsea.

c. Jan and Sharon have never chatted over the Internet.

d. No one in the class has chatted with Bob.

e. Sanjay has chatted with everyone except Joseph.

f. Someone in your class does not have an Internet connection.

g. Not everyone in your class has an Internet connection.

h. Exactly one student in your class has an internet connection.

i. Everyone except one student in your class has an Internet connection.

j. Everyone in your class with an Internet connection has chatted over the Internet with at least one other student in your class.

k. Someone in your class has an Internet connection but has not chatted with anyone else in your class.

l. There are two students in your class who have not chatted with each other over the Internet.

m. There is a student in your class who has chatted with everyone in your class over the Internet.

n. There are at least two students in your class who have not chatted with the same person in your class.

o. There are two students in the class who between them have chatted with everyone else in the class.

Step-by-step explanation:

Note that: Because the arguments are variables, we write

Ix = I(x)

Cxy = C(x,y)

a. Jerry does not have an Internet connection.

~I(Jerry).

b. Rachel has not chatted over the internet with Chelsea.

~C(Rachel,Chelsea).

c. Jan and Sharon have never chatted over the internet.

~C(Jan,Sharon).

d. No one in the class has chatted with Bob.

~∃x C(x, Bob).

e. Sanjay has chatted with everyone except Joseph.

∀y (y ≠ Joseph → C(Sanjay, y)).

f. Someone in your class does not have an internet connection.

∃x ~Ix.

g. Not everyone in your class has an internet connection.

~∀x Ix.

h. Exactly one student in your class has an internet connection.

∃x (Ix ∧ ∀y (Iy → y = x)).

i. Everyone except one student in your class has an internet connection. This means exactly one student does not have a connection.

∃x (~Ix∧ ∀y (Iy → y = x)).

j. Everyone in your class with an internet connection has chatted over the internet with at least one other student in your class.

∀x (Ix → ∃y (Cxy ∧ x ≠ y)).

Assuming nobody can chat with him or herself, then

∀x (Ix → ∃y (Cxy))

k. Someone in your class has an internet connection but has not chatted with anyone else in your class.

∃x (Ix ∧ ∀y ~Cxy).

l. There are two students in your class who have not chatted with each other over the internet.

∃x ∃y (x ≠ y∧~Cxy).

m. There is a student in your class who has chatted with everyone in your class over the internet.

∃x ∀y Cxy.

n. There are at least two students in your class who have not chatted with the same person in your class. ∃x ∃y (x ≠ y ∧ ∃z (~Cxz ∧ ~Cyz)).

o. There are two students in the class who between them have chatted with everyone else in the class.

∃x ∃y (x ≠ y ∧ ∀z (Cxz ∨ Cyz)).

5 0
4 years ago
What is the slope of a line that passes<br> through the points (-1, 1) and (1, -15)?
Alex Ar [27]

Answer:

-8

Step-by-step explanation:

y2 - y1 / x2 - x1

-15 - 1 / 1 - (-1)

= -16 / 2

= -8

6 0
3 years ago
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