All categories

2 years ago

9/2 divided by 2 = 9/2 x2 True or false

Mathematics

2 answers:

Mandarinka [93]2 years ago

5 0

Answer:

false

Step-by-step explanation:

the answer would be false

tatyana61 [14]2 years ago

3 0

<h2>False</h2>

<h3>Verification:</h3>

$\frac{9}{2} \div 2 \\ = \frac{9}{2} \times \frac{1}{2} \\ = \frac{9}{4}$

Hence, Verified

You might be interested in

I USED ALL MY POINTS! PLEASE HELP ME ASAP!!!

Mkey [24]

Answer:

Step-by-step explanation:

50 and 40

8 0

3 years ago

Read 2 more answers

What is the value of a cube with 1/2 inch sides

Serhud [2]

2 is your answer .........

8 0

3 years ago

PLEASE HELP ME WITH THIS QUESTION

valentina_108 [34]

Set 7x-4 and 31 equal to each other
7X-4=31
Add four to both sides
7X=27
X=3
The answer is D

4 0

3 years ago

Read 2 more answers

I know it is a long question but please I will mark brainlist to the person who answers please help

Diano4ka-milaya [45]

Answer:

Carla lives 16 miles from the Library.

The mistake is drawng the diagram incorrectly and using the miles given in the wrong places. The <u>student's</u> diagram has Yuri in a place that's Southwest of the Library in the diagram given

Step-by-step explanation:

If Yuri lives 24 miles SOUTH of the library, the "b" side of the triangle should be 24, with the Library at the top and Yuri at the bottom left, which is the west end of the base. The base "a" of the triangle should extend 10 to the right (East in compas directions) forming the right angle. Carla lives at the sharp southeast corner of the triangle, and the Hypotenuse "c" from her house to the Library is the distance we have to figure.

c² =a² + b²

c² = 10² + 24²

c² = 100 + 576

c² = 676

√c² = √676

c = 26 Carla lives 26 miles from the Library.

3 0

3 years ago

The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term

Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be $1$ , $5$ , and $25$ .

The sum of the first seven terms of the geometric sequence would be $127$ .

Step-by-step explanation:

Let $d$ denote the common difference of the arithmetic sequence.

Let $a_1$ denote the first term of the arithmetic sequence. The expression for the $n$ th term of this sequence (where $n\!$ is a positive whole number) would be $(a_1 + (n - 1)\, d)$ .

The question states that the first term of this arithmetic sequence is $a_1 = 1$ . Hence:

The third term of this arithmetic sequence would be $a_1 + (3 - 1)\, d = 1 + 2\, d$ .
The thirteenth term of would be $a_1 + (13 - 1)\, d = 1 + 12\, d$ .

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let $r$ denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

$\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d$ .

Ratio between the third term and the second term of the geometric sequence:

$\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}$ .

Both $(1 + 2\, d)$ and $\left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right)$ are expressions for $r$ , the common ratio of this geometric sequence. Hence, equate these two expressions and solve for $d$ , the common difference of this arithmetic sequence.

$\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}$ .

$(1 + 2\, d)^{2} = 1 + 12\, d$ .

$d = 2$ .

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be $1$ , $(1 + (3 - 1) \times 2) = 5$ , and $(1 + (13 - 1) \times 2) = 25$ , respectively.

These three terms ( $1$ , $5$ , and $25$ , respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be $r = 25 /5 = 5$ .

Let $a_1$ and $r$ denote the first term and the common ratio of a geometric sequence. The sum of the first $n$ terms would be:

$\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}$ .

For the geometric sequence in this question, $a_1 = 1$ and $r = 25 / 5 = 5$ .

Hence, the sum of the first $n = 7$ terms of this geometric sequence would be:

$\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}$ .

7 0

2 years ago