The figure is made from squares of different sizes.Find the area of A if the side of each of the two indentical smallest square
is 2cm.
1 answer:
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Answer:
6 + 5x³ - 9x² + 2x
Step-by-step explanation:
Given
(3x² - 2x)(2x² + 3x - 1)
Each term in the second factor is multiplied by each term in the first factor, that is
= 3x²(2x² + 3x - 1) - 2x(2x² + 3x - 1) ← distribute both parenthesis
= 6 + 9x³ - 3x² - 4x³ - 6x² + 2x ← collect like terms
= 6 + 5x³ - 9x² + 2x
Solution :
For the bigger rectangle
Width of bigger rectangle = W
Length of bigger rectangle, L = 2W
For the smaller rectangle
Width , w = W+4
Length, l = L = 2W
Area, a =120
Now we know,
Area = length x width
We get, either (rejecting)
or
∴ length of the bigger rectangle,
= 2(6)
= 12 m
Length of the smaller rectangle,
= 2(6)
= 12 m
Hence, the length of the two gardens is 12 m.