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Nataliya [291]
4 years ago
15

A cone-shaped tent has a diameter of 12 ft and a height of 6 ft.

Mathematics
2 answers:
HACTEHA [7]4 years ago
7 0
Volume should be 226.08 
volume of a cone= 1/3 pi radius squared multiplied by height 
6x6=36 multiply by height 36x6=216  divide by 3=72 now multiply by pi =226.08 
your answer is 226.08
Degger [83]4 years ago
7 0

Answer:

226.08

Step-by-step explanation:

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guse lagrange multipliers to find the maximum or minimum values of the function subject to the given constraint. (if an answer d
Novosadov [1.4K]

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

<h3>What is function?</h3>

function, in mathematics, an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable) (the dependent variable) (the dependent variable) (the dependent variable). Mathematics uses functions frequently, and functions are essential for specifying physical relationships in the sciences.

Here,

The function is given as:

f(x,y,z)=x^{2} y^{2} z^{2}

x^{2} +y^{2}+ z^{2}=1

=>x^{2} +y^{2}+ z^{2}-1=0

Using Lagrange multiplies, we have:

L(x,y,z,λ)=f(x,y,z) +λ(0)

Substitute f(x,y,z)=x^{2} y^{2} z^{2}  and x^{2} +y^{2}+ z^{2}-1=0

Differentiate

L(x)=2xy^{2} z^{2}+2λx

L(y)=2yx^{2} z^{2}+2λy

L(z)=2zx^{2} y^{2}+2λz

L(λ)=x^{2} +y^{2}+ z^{2}-1

Equating to 0

2xy^{2} z^{2}+2λx =0

2yx^{2} z^{2}+2λy = 0

2zx^{2} y^{2}+2λz = 0

x^{2} +y^{2}+ z^{2}-1 = 0

Factorize the above expressions

2xy^{2} z^{2}+2λx =0

2x(y^{2} z^{2}+λ)=0

2x=0 and (y^{2} z^{2}+λ)=0

x=0 and  y^{2} z^{2}= -λ

2yx^{2} z^{2}+2λy = 0

2y(x^{2} z^{2}+λ)=0

2y=0 and (x^{2} z^{2}+λ)=0

y=0 and  x^{2} z^{2}= -λ

2zx^{2} y^{2}+2λz = 0

2z(y^{2} x^{2}+λ)=0

2z=0 and (x^{2} y^{2}+λ)=0

z=0 and  x^{2} y^{2}= -λ

So we have ,

x=0 and  y^{2} z^{2}= -λ

y=0 and  x^{2} z^{2}= -λ

z=0 and  x^{2} y^{2}= -λ

The above expression becomes

x=y=z=0

This means that,

x^{2} +y^{2}+ z^{2}=1

x^{2} +x^{2}+ x^{2} =1 \\3x^{2 } =1

x= ±1/\sqrt{3}

So,

y= ±1/\sqrt{3}

z= ±1/\sqrt{3}

The critic points are

x=y=z=±1/\sqrt{3}

x=y=z=0

Therefore the maximum value of function f(x,y,z)=x^{2} y^{2} z^{2} =1/27

And the minimum value is 0

To know  more about function , visit

brainly.com/question/12426369

#SPJ4

3 0
1 year ago
Some friends played a board game. During the game, one unlucky player had to move back 8 spaces
podryga [215]
Yes 4+*2 34^%7 shehshshs
6 0
3 years ago
What is the cube root for 3000??
Alona [7]
\sqrt[3]{3000}=\sqrt[3]{1000\times3}=\sqrt[3]{1000}\times\sqrt[3]3=10\sqrt[3]3
4 0
3 years ago
Read 2 more answers
Do the table and the equation represent the<br> same function?<br> y = 390 + 11(x)
Aneli [31]

Answer:

NO

Step-by-step explanation:

  • Try to replace x by -50
  • y= 390 + 11*(-50) = -160
  • in the table we have -210 so the table doesn't represent the equation
5 0
3 years ago
Find the area of the figure.<br><br>12 ft<br>18 ft<br>18 ft<br>36 ft​
Nataly_w [17]

Answer:

139968

Step-by-step explanation:

Multiply the all of the numbers together and you have your answer (:

7 0
3 years ago
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