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Licemer1 [7]
3 years ago
12

The volume of a cube is related to the area of a face by the formula V = A^3/2What is the volume of a cube whose face has an are

a of 100 cm??
helppp!!

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

\huge\boxed{1000 \ \text{cm}^3}

Step-by-step explanation:

There are two ways we can solve this equation.

<h2>A) Using the formula provided</h2>

The formula provided states that the volume of a cube based on the area of one of it's faces will be a^{\frac{3}{2}}, a the area of one face. Since we know the area of one face, we can substitute that inside the equation.

100^{\frac{3}{2}}

It's important to note that when we have a number to a fraction power, it's the same as taking the denominator root of the base to the numerator power.

So - 100^{\frac{3}{2}} becomes \sqrt{100^3}

  • 100^3=1000000
  • \sqrt{1000000}=1000

Therefore, the volume of this cube will be 1000 \ \text{cm}^3

<h2>B) Using prior knowledge about cubes</h2>

We can additionally use prior knowledge to find the volume of this cube.

We know that the area of a square will be s^2, where s is the length of a side. We also know the formula to find the volume of a cube from it's side length is s^3.

Since we know that one face is 100, we can make an equation - s^2=100

  • \sqrt{s^2}=\sqrt{100}
  • s=10

Now that we know the value of s, we can plug it into the volume formula, s^3.

  • 10^3
  • 10 \cdot 10 \cdot 10
  • 1000

So the volume is 1000 \ \text{cm}^3.

Hope this helped!

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Step-by-step explanation:

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The system of standard automotive license plates allows for a variety of standard plates is 39917124 ways.

<h3>Define the term permutation?</h3>
  • The number of potential arrangements for a given set is assessed mathematical terms, but this procedure is referred to as permutation.
  • The arrangement's order is essential when using permutations.

For the stated data;

Standard car license plates in a nation typically have 3 digits, 2 letters, and 2 numbers.

There are total 9 digits (0 - 9).

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Repetitions of letters and numbers given allowed.

Thus, numbers and the letters ca be arranged as;

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