Margin of error, e = Z*SD/Sqrt (N), where N = Sample population
Assuming a 95% confidence interval and substituting all the values;
At 95% confidence, Z = 1.96
Therefore,
0.23 = 1.96*1.9/Sqrt (N)
Sqrt (N) = 1.96*1.9/0.23
N = (1.96*1.9/0.23)^2 = 262.16 ≈ 263
Minimum sample size required is 263 students.
<h2>
Answer:</h2>
<h3>True</h3>
<h2>
Step-by-step explanation:</h2>
<h3>Intrusive rocks, have large crystals that are usually visible without a microscope. </h3>
<h2>Therefore it's true. </h2>
<h2>Hope it help you </h2>
Answer:
C. 309 cm2
Step-by-step explanation:
A=2(1+sqr2)a^2
A=2(1+sqr2)8^2
≈309.01934
5*23
Note 23 = 20 + 3
5*23 = 5*(20 + 3) and by distributive property
5*23 = 5*20 + 5*3 = 100 + 15 = 115
= 115
