An angle that is inscribed in a semi-circle is equal to a right triangle
Answer:
<T = 81
x = 10, angle = 60
Angle 5 and Angle 3 are vertical angles. They are acute angles
Step-by-step explanation:
Supplementary angles add to 180
(7x+11) + (8x+19) = 180
Combine like terms
15x + 30 = 180
Subtract 30 from each side
15x +30-30 = 180-30
15x= 150
Divide by 15
15x/15 = 150/15
x = 10
We want angle T
T = 7x+11 = 7(10)+11 = 70+11 = 81
The two angles add to 90
5x+10 + 30 = 90
Combine like terms
5x+40 = 90
5x+40-40 = 90-40
5x = 50
Divide by 5
5x/5 = 50/5
x=10
5x+10 = 5(10) +10 = 50+10 = 60
Angle 5 and Angle 3 are vertical angles. They are acute angles
I think it’s 16 remainder 1
Answer:
2
Step-by-step explanation:
For any positive numbers a,b we always have the following identity:
(gcd(a,b) denotes the greatest common divisor between a and b, and lcm(a,b) denotes the least common multiple between a and b)
In our case, we are given that and that . Plugging that in into our identity, we get:
And so solving for :
<u>Answer:</u>
7 inches
<u>Step-by-step explanation:</u>
The dimension of the rectangular gift is 10 by 12 inches so let us find the perimeter of this rectangle.
Perimeter of rectangular gift = 2 (L+ W) = 2 (10 +12) = 44 inches
Since we are to use the same length of ribbon to wrap a circular clock so the perimeter or circumference of the clock should be no more than 44 inches.
Therefore, the maximum radius of the circular clock is 7 inches.