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2 years ago

Add. 8x - 7 + 6x + 8 Help. I might be dumb for not knowing this but please help

Mathematics

2 answers:

Lelu [443]2 years ago

8 0

Answer:

Step-by-step explanation:

nydimaria [60]2 years ago

7 0

Answer:

14 x + 1

Step-by-step explanation:

You aren't dumb, your teacher can't teach!

First we must add the x values together:

8x - 7 + 6x + 8

8 + 6 = 14

14x -7 + 8

Now we add the constants (regular numbers):

14x -7 + 8

-7 + 8

14x +1

There we go!

8x -7 + 6x +8

14x +1

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A pharmacy claims that the average medication costs $32 but it could differ as much as $8. Write and solve an absolute value ine

Vinil7 [7]

Answer:

Therefore, Option C is correct that is $|x-32|\leq8|{\text{the medication costs range from $24to $40}$ .

Step-by-step explanation:

We have given medication cost $32

Since, we have given as much as 8 so the inequality will maximum goes upto 8.

$|x-32|\leq8$

Now, we will solve the inequality for x we will get

We will first open the modulus function by its definition we will get

which is |x| is +x and -x

$(x-32)\leq8$

$x=32+8=40$

$x=40$

And $-(x-32)\leq8$

$-x+32=8$

$x=24$

Therefore, Option C is correct

8 0

3 years ago

Read 2 more answers

Which words in the sentence are the complete noun clause?

asambeis [7]

C. whoever comes into the house

7 0

3 years ago

Read 2 more answers

Please help me with this geometry problem, tysm

mixas84 [53]

9514 1404 393

Answer:

x = 6
∠NBS = 68°

Step-by-step explanation:

The sum of the two adjacent angles is equal to the angle that includes both.

∠NBS +∠SBR = ∠NBR . . . . . angle sum theorem

(12x -4) +42 = (17x +8)

30 = 5x . . . . . . . . . . . . . . subtract 12x+8

6 = x . . . . . . . . divide by 5

Then the measure of ∠NBS is ...

∠NBS = 12x -4 = 12·6 -4

∠NBS = 68 . . . . degrees

4 0

2 years ago

Find the absolute maximum and minimum values of the following function in the closed region bounded by the triangle with vertice

alukav5142 [94]

$f(x,y)=2x^2-8x+y^2-8y+2$

$f_x(x,y)=4x-8=0\implies x=2$

$f_y(x,y)=2y-8=0\implies y=4$

There is one critical point at (2, 4), but this point happens to fall on one of the boundaries of the region. We'll get to that point in a moment.

Along the boundary $x=0$ , we have

$f(0,y)=y^2-8y+2=(y-4)^2-14$

which attains a maximum value of

$f(0,4)=-14$

Along $y=44$ , we have

$f(x,44)=2x^2-8x+1586=2(x-2)^2+1578$

which attains a maximum of

$f(2,44)=1578$

Along $y=2x$ , we have

$f(x,2x)=6x^2-24x+2=6(x-2)^2-22$

which attains a maximum of

$f(2,4)=-22$

So over the given region, the absolute maximum of $f(x,y)$ is 1578 at (2, 44).

8 0

2 years ago

A gambler is deciding whether or not to take a bet. She must pay $40 to take the bet, but if she wins, she will profit $225. The

kicyunya [14]

Answer:

The classification of that same given problem is outlined in the following portion on the clarification.

Step-by-step explanation:

⇒ $E[x]=\Sigma_{x=0}^{x} \ x \ f(x)$

On putting the values, we get

⇒ $=0\times \frac{3}{4}+225\times \frac{1}{4} -40\times 1$

⇒ $=\frac{225}{4}-40$

On taking L.C.M, we get

⇒ $=\frac{225-160}{4}$

⇒ $=\frac{65}{4}$

⇒ $=16.25$

1...

Whether she wins she would receive $225 with even a 1/4 chance, then she will lose and maybe get $0 with such a 3/4 chance although if she takes a gamble anyway though she will either have to compensate $40 wp 1.

2...

She seems to want the capital to benefit or win.

6 0

3 years ago