1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
maksim [4K]
3 years ago
14

Lola bought x pencils that cost $0.25 each and y erasers that cost $0.50. She spent less than $3. Which graph represents Lola’s

purchase? Image for option 1 Image for option 2 Image for option 3 Image for option 4
Mathematics
2 answers:
ValentinkaMS [17]3 years ago
6 0
I thing you forfot to ipload the graphs! I see no graphs to choose from, just the question itself! Please provide to graphs in order to help. Thanks
TEA [102]3 years ago
5 0

Answer:

Graph C is the answer.

step by step explanation:

Lola bought X pencils that cost $0.25 and Y erasers that cost $0.50.

Total expenditure is less than $3.

If we represent expense in the equation form then it will be

Expense on pencils + expense on erasers = Total expense which is < 3

0.25X + 0.50Y < 3

Now we divide the inequality by 0.25

X + 2Y < 12

This inequality when graphed, line will be plotted in dots and area below the line will be in the shaded form.

Slope of this line is = (-1/2) {from the standard equation of line y = mx + c)

Now we come to the graphs. Here dotted line graphs are A or C.

We will calculate the slopes of the lines from the graphs A and C to get tha answer.

For Graph A

The end points are (12, 0) and (0, 3)

So slope = (y-y')/(x-x') = (3-0)/(0-12) = -3/12 = -1/4

For Graph C.

End points the line are (0, 6) and (12, 0)

Slope of the line = (0-6)/(12-0) = -6/12 = -1/2

Therefore Graph C is the answer.

You might be interested in
Select each situation that can represent a proportional relationship
Oduvanchick [21]

Answer:

is it a a,b,c,d picked answer or???

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Please, ASAP help 20 points
koban [17]
Yeah you use the app called slazo
5 0
3 years ago
A collection of 30 gems, all of which are identical in appearance, are supposedto be genuine diamonds, but actually contain 8 wo
levacccp [35]

Answer:

Step-by-step explanation:

From the given information:

There are 30 collections of gems, of which 8 are worthless;

Thus, the number of the genuine diamonds = 30 - 8 = 22.

Let X = random variable;

X consider the value as 0 (for  2 worthless stone selection),

X = 1200(1 worthless stone  & 1 genuine stone)

X = 2400 (2 genuine stones selected)

However, the numbers of ways of selecting and chosen Gems can be estimated as:

(^n_r) = (^{30}_2) \\ \\ \implies \dfrac{30!}{2!(30-2)!} \\ \\ \implies \dfrac{30!}{2!(28)!}  \\ \\  \implies \dfrac{30*29*28!}{2!(28)!} \\ \\  \implies  \dfrac{30*29}{2*1} \\ \\ \implies 435

Thus;

Pr (X = 0) = \dfrac{(^8_2)}{435}

Pr (X = 0) = \dfrac{\dfrac{8!}{2!(8-2)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8!}{2!(6)!}}{435}  \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7*6!}{2!(6)!}}{435} \\ \\  Pr (X = 0) = \dfrac{\dfrac{8*7}{2*1}}{435} \\ \\   Pr (X = 0) = 0.0644

P(X =1200) = \dfrac{(^{8}_{1})(^{22}_{1})}{435}

P(X =1200) = \dfrac{ \dfrac{8!}{1!(8-1)!}) ( \dfrac{22!}{1!(22-1)!}) }{435}

P(X =1200) = \dfrac{ (8) ( 22) }{435}

P(X =1200) =0.4046

Pr (X = 2400) = \dfrac{(^{22}_2)}{435}

Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(22-2)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(20)!}}{435}  \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22*21*20!}{2!(20)!}}{435} \\ \\  Pr (X =2400) = \dfrac{\dfrac{22*21}{2*1}}{435} \\ \\   Pr (X = 2400) = 0.5310

To find E(X):

E(X) = (0 × 0.0644) + (1200 × 0.4046)  + (2400 × 0.5310)

E(X) = 0 + 485.52 + 1274.4

E(X) = 1759.92

8 0
3 years ago
Find the value of x​
svp [43]
X equals x because x is theoretically x the letter
4 0
3 years ago
Read 2 more answers
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be
babymother [125]

Answer:

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

Step-by-step explanation:

Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.

If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.

This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.

In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.

8 0
3 years ago
Other questions:
  • Help me please<br><br> If you help me I would appreciate it a lot
    10·1 answer
  • Consider the put-call parity relationship for European call and put options on a stock that pays discrete dividends only. Assume
    15·1 answer
  • Write the following as inequalities<br> Domain=<br> Range=
    15·1 answer
  • A GE lightbulb is supposed to last for 1,200 hours. In fact, light bulbs of this type last only 1,185 hours with a standard devi
    9·1 answer
  • What value is equivalent to -3 x 32 - 8 ÷ 2 + 6? -18 -7 -16 7
    7·2 answers
  • Help please can't figure out
    10·1 answer
  • Somebody help me fast<br> This is correct?!
    9·1 answer
  • I need help asap plsssss!!!
    8·1 answer
  • Whats a good nickname for my friend David?
    15·1 answer
  • Solve this for me please
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!