Step-by-step explanation:
lol! thanks for the point
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Answer:
The probability that the total weight of the passengers exceeds 4222 pounds is 0.0018
Step-by-step explanation:
The Central limit Theorem stays that for a large value of n (21 should be enough), the average distribution X has distribution approximately normal with mean equal to 182 and standard deviation equal to 30/√21 = 6.5465. Lets call W the standarization of X. W has distribution approximately N(0,1) and it is given by the formula

In order for the total weight to exceed 4222 pounds, the average distribution should exceed 4222/21 = 201.0476.
The cummulative distribution function of W will be denoted by
. The values of
can be found in the attached file.

Therefore, the probability that the total weight of the passengers exceeds 4222 pounds is 0.0018.
Answer:yes
Step-by-step explanation:
Answer:
$70 >= $61.50 + $5x
Step-by-step explanation:
With the values provided the only variable would be the number of gigabytes. Since Hunter does not want to spend more than $70 then the value of the amount of money he is paying for gigabytes plus the flat cost needs to be less than or equal to $70. Therefore, the following inequality would represent this scenario best...
$70 >= $61.50 + $5x
Answer:
<h2>D.

or StartFraction x squared + 3 x minus 12 Over (x + 3) (x minus 5) (x + 7) EndFraction</h2>
Step-by-step explanation:
Given the expression
, the dfference is expressed as follows;
Step1: First we need to factorize the denominator of each function.

Step 2: We will find the LCM of the resulting expression

The final expression gives the difference