All categories

3 years ago

2x + 46 + 3x - 6 I forgot how to do math

Mathematics

2 answers:

sukhopar [10]3 years ago

7 0

Answer: hope this helps

Step-by-step explanation:

5 (x + 8)

Root:

x = -8

Derivative:

d/dx(2 x + 46 + 3 x - 6) = 5

Indefinite integral:

integral(40 + 5 x) dx = (5 x^2)/2 + 40 x + constant

blondinia [14]3 years ago

4 0

Answer:

5x-40=0

5x=40

x=40/5

x=8

You might be interested in

Question 3 Solve for m. 4 over 3 m equals 4

Lorico [155]

Answer:

$m = 3$

Step-by-step explanation:

$\frac{4}{3} m = 4 \\ divide \: both \: sides \: by \: \frac{4}{3} \\ \\ m = 3$

3 0

3 years ago

Nifal earned 9$ for washing two cars .He recived $1 more for the second car.How much was he paid for washing each car?Which two

Sveta_85 [38]

Answer:

Nifal received $ 4 for washing the first car.

Nifal received $ 5 for washing the second car.

4 and 5 have a sum of 9.

Step-by-step explanation:

The problem can be rewritten as follows: Find the sum of two consecutive entire numbers equal to 9. That is:

$x + y = 9$

$y = x+1$

Then, by eliminating y:

$x + (x+1) = 9$

$2\cdot x + 1 = 9$

Now, let is clear $x$ :

$2\cdot x = 8$

$x = 4$

Nifal received $ 4 for washing the first car.

The earning for the second car is: ( $x = 4$ )

$y = x +1$

$y = 4 + 1$

$y = 5$

Nifal received $ 5 for washing the second car.

4 and 5 have a sum of 9.

8 0

3 years ago

when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%

Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%

Selling price = cost price - discount ⇒ discount case
Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = $\frac{160}{90}=\frac{16}{9}$

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = $\frac{20}{100}$ × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by $\frac{16}{9}$ to find x

∵ 0.8x = $\frac{16}{9}$

- Divide both sides by 0.8

∴ x = $\frac{20}{9}$

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is $\frac{20}{9}$

- Find 20% of $\frac{20}{9}$

∵ Profit = 20% × $\frac{20}{9}$ = $\frac{20}{100}.\frac{20}{9}=\frac{4}{9}$

- Add $\frac{4}{9}$ to cost price to find the selling price

∴ The selling price of an orange = $\frac{20}{9}$ + $\frac{4}{9}$

∴ The selling price of an orange = $\frac{24}{9}$

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ $\frac{24}{9}$

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0

3 years ago

I have finished the table but stuck in the question after...

lisov135 [29]

Answer:

7/48

Step-by-step explanation:

there are 48 in total

there are 7 white females

7/48

4 0

4 years ago

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers. Roun

AlekseyPX

Answer:

P = 0.008908

Step-by-step explanation:

The complete question is:

The table below describes the smoking habits of a group of asthma sufferers

Nonsmokers Light Smoker Heavy smoker Total

Men 303 35 37 375

Women 413 31 45 489

Total 716 66 82 864

If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.

The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

$nCx=\frac{n!}{x!(n-x)!}$

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

$82C2=\frac{82!}{2!(82-2)!}=3321$

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

$864C2=\frac{864!}{2!(864-2)!}=372816$

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:

$P=\frac{82C2}{864C2}=\frac{3321}{372816}=0.008908$

4 0

3 years ago