Answer:
ΔT = ΔT0 e^-K T
As I understand Newton's Law of Cooling
ΔT at any time is the difference between the temperature and the surroundings
Originally ΔT0 = 95 - 22 difference between 95 and room temperature
65 - 22 = 33 = 73 e^-KT where t is time to cool to 65 deg
ln (33/73) = -KT K = .794 / 5 = .159 where 5 is time to cool to 65 deg
40 - 22 = 73 e^-.159 T where t is time to cool to 40 deg
18 = 73 e^-.159 T
ln (18 / 73) = -.159 T
T = 8.8 min
It would take 8.8 min for the object to cool to 40 deg C
Suppose the object cooled from 95 to 90 deg, then
ln 68 / 73 = -.159 T and T = .45 min
Answer:
c
Step-by-step explanation:
We know that the average temperature surface in neptune is : - 210 degree Celsius
Thee average temperature surface in mars is : -85 degree Celsius
The net change would be an increase in 125 degree celsius<span />
<h3>Answer: Choice A) x+14</h3>
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Work Shown:
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (f(x)) - (g(x))
(f-g)(x) = (3x+10) - (2x-4)
(f-g)(x) = 3x+10 - 2x+4
(f-g)(x) = (3x-2x) + (10+4)
(f-g)(x) = x+14
Answer:
RD = 162 cm
Step-by-step explanation:
LD = 2 RL = 2* 54 = 108
RD = RL + LD
RD = 54 + 108
RD = 162 cm
