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3 years ago

Which type of function is shown in the table below?

Mathematics

1 answer:

Ksju [112]3 years ago

6 0

Answer:

2 15 sorry po kung mali

Step-by-step explanation:

Wala pong step by step

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I need help with the question below

Butoxors [25]

Answer:

a: 1/12

b: 1/6

c: 1/2

d: 1/2

e: 1/12

f: 1/3

Step-by-step explanation:

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3 years ago

I need help with 1/4x- 3=1/2x+12

kaheart [24]

Solve for x by simplifying both sides of the equation, then isolating the variable.
x =−60

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3 years ago

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Could I have some help please

Contact [7]

Sure what’s the question

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3 years ago

Plzz help no. 6 rate

Makovka662 [10]

Step-by-step explanation:

If 200 g fertiliser required for 8 m^2 then for 1m^2 we'd need 25 g of fertiliser

(i) 14×25 = 350 g fertiliser would be needed for 14 m^2 land

(ii) 450÷25 = 18 m^2 land could be fertilised with 450 g fertiliser

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3 years ago

Among all right circular cones with a slant height of 24, what are the dimensions (radius and height) that maximize the volum

aleksklad [387]

Answer:

5571.99

Step-by-step explanation:

We need to use the Pythagorean theorem to solve the problem.

The theorem indicates that,

$r^2+h^2=24^2 \\r^2+h^2=576\\r^2=576-h^2$

Once this is defined, we proceed to define the volume of a cone,

$v=\frac{1}{3}\pi r^2 h$

Substituting,

$v=\frac{1}{3} \pi (576-h^2)h\\v=\frac{1}{3} \pi (576h-h^3)$

We need to find the maximum height, so we proceed to calculate h, by means of its derivative and equalizing 0,

$\frac{dv}{dh} = \frac{1}{3} \pi (576-3h^2)$

$\frac{dv}{dh} = 0$ then $\rightarrow \frac{1}{3}\pi(576-3h^2)=0$

$h_1=-8\sqrt{3}\\h_2=8\sqrt{3}$

<em>We select the positiv value.</em>

We have then,

$r^2 = 576-(8\sqrt3)^2 = 384\\r=\sqrt{384}$

We can now calculate the maximum volume,

$V_{max}= \frac{1}{3}\pi r^2 h = \frac{1}{3}\pi (\sqrt{384})^2 (8\sqrt{3}) = 5571.99$

4 0

3 years ago