Question

What is the eqaution of a circle with center (2,-10) and radius 3​

Answer 1

Answer:

x2+y2−4x+20y+4=0.

Explanation:

The eqn. of a circle with centre (h,k) and radius r is given by,
(x−h)2+(y−k)2=r2.
Accordingly, the reqd. eqn. is,
(x−2)2+(y+10)2=3^2, i.e.,
x2+y2−4x+20y+4=0.