Im confused on how you typed your problem.
You will have to use trial and error in order to find the values for x and y.
Just keep plugging values until you get 7.
I found x is equal to 2 and y is equal to 5.
3(2) + (1/5)5 = 7
6 + 5/5 = 7
6 + 1 = 7
7 = 7
Answer:
20 students.
Step-by-step explanation:
The <u>first </u>person said 5 (which is 5 x 1), the <u>second </u>person said 10 ( which is 5 x2)... we see that this is a arithmetic sequence where the first term is 5 and the nth term is 100. We know that 100 = 5 x 20, therefore, the number of students that counted all the way up to 100 was 20 and Bobby was wrong.
[1], [3] => a = 49,000/2 = 24,500 => b +c = 24,500 => c = 24,500 - b;
[2] => 25*24,500 + 20b + 15c = 1,052,000 => 20b + 15c = 1,027,500;
20b + 15*(24,500 - b) = 1,027,500 => 5b = 733,500 => b = 146,700 =>
c = - 122,200;
