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kakasveta [241]
3 years ago
6

The length of a rectangle is 6 cm longer than its width.

Mathematics
1 answer:
sergey [27]3 years ago
7 0
L= 6+w
6+2w=36
-6 -6
2w=30
w=15; l= 21
15x21= 315
A=315
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Two ladders are leaning against a building, forming two similar triangles as shown below. The top of the longer ladder is 28 fee
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Answer:

The length of the longer ladder is 35 ft

Step-by-step explanation:

Please check the attachment for a diagrammatic representation of the problem

We want to calculate the length of the longer ladder ;

We make reference to the diagram

Since the two right triangles formed are similar. the ratios of their sides are equal;

Thus;

20/15 = 28/x + 15

20(x + 15) = 15(28)

20x + 300 = 420

20x = 420-300

20x = 120

x = 120/20

x = 6

So we want to calculate the hypotenuse of a right triangle with other sides 28ft and 21 ft

To do this, we use the Pythagoras’ theorem which states that square of the hypotenuse equals the sum of the squares of the two other sides

Let the hypotenuse be marked x

x^2 = 28^2 + 21^2

x^2 = 1,225

x = √1225

x = 35 ft

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Step-by-step explanation:

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Do I need to put parentheses in this? Why it why not?
Oksana_A [137]

Answer:

Parentheses can change the result of the answer. If you want to add 4 and 0.95 first, then multiply that number by 3, then you need parentheses.

Step-by-step explanation:

When you are given the question 3 X 4 + 0.95, it has to types of operations. <u>People solve using the order PEDMAS</u>:

Parentheses,

Exponents,

Division and Multiplication,

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Since there are <u>no parentheses</u> or exponents, the solver will do multiplication first, then addition.

3 X 4 + 0.95     Multiply first

= 12 + 0.95       Now add

= 12.95         Answer without parentheses

If you add <u>parentheses around 4 + 0.95</u>, the answer would change. According to PEDMAS, the parentheses must be solved before anything else.

3 X (4 + 0.95)       Add inside parentheses

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If you added <u>parentheses around 3 X 4</u>, the answer would not change, because you still multiply first.

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