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anygoal [31]
3 years ago
9

Which of the terms given can you right in the butt in the box so that the equation will be infinity many solutions 4x-36=. (X-9)

Mathematics
1 answer:
pashok25 [27]3 years ago
8 0
I donno. 83828728873
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(add. write your answer as a fraction, as a whole or as a mixed number)
Eduardwww [97]

Answer:

3 and 1/12

Step-by-step explanation:

hope this helps! :)

5 0
3 years ago
How many marbles must be in the 8th line ? 
Nat2105 [25]

Answer:

?? Which line

7 0
3 years ago
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Factor sec^2x-secx+tan^2x
marysya [2.9K]

Answer:

sec²(x) - sec(x) + tan²(x) = (sec(x) - 1)(2sec(x) + 1)

Step-by-step explanation:

sec²(x) - sec(x) + tan²(x) =

= sec²(x) - sec(x) + [sec²(x) - 1]

= sec²(x) - sec(x) + [(sec(x) + 1)(sec(x) - 1)]

= sec(x)[sec(x) - 1] + [(sec(x) + 1)(sec(x) - 1)]

= (sec(x) - 1)(sec(x) + sec(x) + 1)

= (sec(x) - 1)(2sec(x) + 1)

6 0
3 years ago
PLEASE HELP I AM BEING TIMED!!
Amiraneli [1.4K]

Answer:

X=1.2

Step-by-step explanation:

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3 0
3 years ago
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Hey, Its the same person. This is Algebra 2. Please Help!
suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = \frac{2x^2+5x-12}{x+4} ← factorise the numerator

     = \frac{(x + 4)(2x-3)}{x+4} ← cancel (x + 4) on numerator/ denominator

     = 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

To obtain the zero let f(x) = 0, that is

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

There is a zero at ( \frac{3}{2}, 0 )

Thus

discontinuity at (- 4, - 11 ), zero at ( \frac{3}{2}, 0 )

7 0
3 years ago
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