Answer:
The digit that should be placed in the blank is 0.
Step-by-step explanation:
We are given the four-digit number: 138_
And we want to determine the digit that should be placed in the blank to make the number be divisible by both 4 and 5.
A number that is divisible by 5 must end in either 0 or 5. This leaves us with only two options: 1380 or 1385.
Recalling divisibility rules, for a number to be divisible by 4, its last two digits must be divisible by 4.
80 is indeed divisible by 4, while 85 is not.
In conclusion, the digit that should be placed in the blank is 0, with the number being 1380.
Answer:
Step-by-step explanation:
Let n = the number of prints
and C = the total cost.
At the regular price, the formula is
C = 1.45n
During the promotion, you must pay for the first nine prints: 9 × 1.45 = 13.05.
For anything over nine prints (n - 9), you must pay $13.05 plus the promotional cost of $1.10 for each print. The promotional formula is
C = 13.05 + 1.10(n - 9) {n > 9}
1. Calculate the cost of 19 prints
2. What number of the prints is a waste of money?
During the promotion, buying fewer than nine prints would be a waste of money, because you would not be taking advantage of the promotional savings.
Answer:
2400000 in a hour
Step-by-step explanation:
40,000 × 60 = 2400000 you need to multiple 40,000 with 60 because there is 60 minutes in a hour
Answer:
y - 2 = (-3/7)(x + 5)
Step-by-step explanation:
Recall that the slopes of a line and another line perpendicular to the first are negative reciprocals.
The slope of the given line is 7/3. The negative reciprocal of that is -3/7. Thus, we immediately eliminate the fourth answer choice.
We must now find the equation of the perpendicular line, with slope -3/7, that passes through (-5, 2). We'll do that using the point-slope formula for the equation of a straight line.
That formula is y - k = m(x - h), where m is the slope and (h, k) is the given point.
Substituting 2 for k, -5 for h and -3/7 for m, we get:
y - 2 = (-3/7)(x + 5). This matches the 3rd given possible answer.
