(3x-5)(2x-7)
6x^2 - 21 x -10x +35
6x^2 -31x +35
The first one
The solution is B = 43
Step-by-step explanation:
Simplify and solve for the unknown for 5(B + 3) = 4(B - 7) + 2B
- Simplify each side
- Add the like terms in each side if need
- Separate the unknown in one side and the numerical term in the other side to find the value of the unknown
∵ 5(B + 3) = 4(B - 7) + 2B
- Multiply the bracket (B + 3) by 5 in the left hand side and multiply
the bracket (B - 7) by 4 in the right hand side
∵ 5(B + 3 ) = 5(B) + 5(3) = 5B + 15
∵ 4(B - 7) = 4(B) - 4(7) = 4B - 28
∴ 5B + 15 = 4B - 28 + 2B
- Add the like terms in the right hand side
∵ 4B + 2B = 6B
∴ 5B + 15 = 6B - 28
- Add 28 to both sides
∴ 5B + 43 = 6B
- Subtract 5B from both sides
∴ 43 = B
- Switch the two sides
∴ B = 43
To check the answer substitute the value of B in each side if the two sides are equal then the solution is right
The left hand side
∵ 5(43 + 3) = 5(46) = 230
The right hand side
∵ 4(43 - 7) + 2(43) = 4(36) + 86 = 144 + 86 = 230
∴ L.H.S = R.H.S
∴ The solution B = 43 is right
The solution is B = 43
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The answer is 25 because of the Pythagorean theorem. 49+576=625 625 squared=25
Let the total no. of 25 p coins be x
50p coins = 2x
Value of 25 p coins ( in rupees) = 0.25*x =0.25x
Value of 50p coins ( in rupees) = 0.5*2x = x
0.25x+x = 25
1.25x =25
x = 25/1.25 = 20
no. if 25p coins = 20
and 50p coins = 2*20 = 40
