On a graph then it is in the top left of the grid.
The 8 is in the tenths place it would look like 8/10 .8 its .08 for 8/100
Answer:
7.3% of the bearings produced will not be acceptable
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.
So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.
Larger than 0.504
1 subtracted by the pvalue of Z when X = 0.504.



has a pvalue of 0.9938
1 - 0.9938= 0.0062
Smaller than 0.496
pvalue of Z when X = -1.5



has a pvalue of 0.0668
0.0668 + 0.0062 = 0.073
7.3% of the bearings produced will not be acceptable
Answer:
cos theta = 4/5
Step-by-step explanation:
Since this is a right triangle
Cos theta = opp side/ hypotenuse
Cos theta = 8/10
cos theta = 4/5
Answer:
A. is incorrect. He has to divide 76 by 19, instead of subtracting 19 to 76.
B. This equation has one solution. v=4
Step-by-step explanation:
Hi, Martin’s answer is incorrect.
A. He has to divide 76 by 19, instead of subtract 19 to 76.
The correct steps are:
19v = 76
Since 19 is multiplying the variable, to eliminate it we have to divide by 19.
v = 76/19
v = 4
B. This equation has one solution. It’s v=4
Feel free to ask for more if needed or if you did not understand something.