2 years ago

BRAINLIEST! NEED HELP ASAP! (please put the right answer & as an equation)

Mathematics

1 answer:

Vera_Pavlovna [14]2 years ago

7 0

Y=1/5x-7 Hope this helps!

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Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf

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The table is missing in the question. The table is provided here :

Group 1 Group 2

34.86 64.14 mean

21.99 20.46 standard deviation

7 7 n

Solution :

a). The IV or independent variable = Group 1

The DV or the dependent variable = Group 2

b).

$H_0: \mu_1 = \mu_2$

$H_a:\mu_1 < \mu_2$

Therefore, $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now, $df = min(n_1 - 1, n_2 - 1)$

df = 7 - 1

= 6

Therefore the value of p :

$=T.DIST(-2.579143,6,TRUE)$

= 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

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