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3 years ago

Place the indicated product in the proper location on the grid (x+y+3)(x+y-4)

Mathematics

1 answer:

pashok25 [27]3 years ago

6 0

Solution:

we have been asked to find the product of (x+y+3)(x+y-4).

we will multiply term by term as below

$(x+y+3)(x+y-4)=x(x+y+3)+y(x+y+3)-4(x+y+3)\\\\\ (x+y+3)(x+y-4)=x^2+xy+3x+xy+y^2+3y-4x-4y-12\\\\\text{Now take the like terms together and simplify we get}\\\\(x+y+3)(x+y-4)=x^2+y^2+2xy-x-y-12\\$

Hence the the product of (x+y+3)(x+y-4) is $x^2+y^2+2xy-x-y-12$

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Find the area of this figure (50 points)

Softa [21]

Answer:

$A_{total} = 14\ in^2$

Step-by-step explanation:

Step 1: Determine the area of the left rectangle

We can tell that the total shape seems like two rectangles glued together. We can separate the left rectangle and determine the area of it and then determine the area of the right rectangle and combine them. Lets first solve the left rectangle.

$A = l * w$

$A_{left\ rectangle} = 2\ in * 4\ in$

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Step 2: Determine the area of the right rectangle

$A = l * w$

$A_{right\ rectangle} = 3\ in * 2\ in$

$A_{right\ rectangle} = 6\ in^2$

Step 3: Determine the total area

$A_{total}=A_{left\ rectangle} + A_{right\ rectangle}$

$A_{total} = 8\ in^2 + 6\ in^2$

$A_{total} = 14\ in^2$

Answer: $A_{total} = 14\ in^2$

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2 years ago

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A ray bisects an obtuse angle into two congruent angles. what type of angles are these two congruent angles?

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Angle bisector? I'm not sure sorry

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3 years ago

The midpoint between x and 27 is -3

maw [93]

Answer: x = -33

Step-by-step explanation:

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An urn contains ten marbles, of which give are green, two

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Answer:

$\frac{5\cdot 4\cdot 3}{10\cdot 9 \cdot 8}\approx 0.083$

Step-by-step explanation:

Getting all three marbles of green color only happens if every draw is a green marble. On the first marble draw, the urn has 10 marbles in it, out of which 5 are green. So the probability of drawing a green marble on this first draw is $\frac{5}{10}$

Then, once this has happened, the second draw also needs to be a green marble. At this point in the urn there are only 9 marbles left, and only 4 of them are green. So the probability of drawing a green marble at this point is $\frac{4}{9}$

Afterwards, on the last draw, a green marble also needs to be drawn. At this point there are only 8 marbles left on the urn, and only 3 of them are green. So the probability of drawing a green marble on this last draw is $\frac{3}{8}$