To get an average score of 80% (out of four exams), a total of 4*80%=320% is needed, so the minimum required for the 4th test is 320-(75+97+60)=88.
To get an average score of 89% (out of four exams), a total of 4*89%=356% is needed, so the maximum required for the 4th test is 356-(75+97+60)=124, which is impossible.
So the next exam grade must range between 88 and 100 to get a grade b in the class.
Hoped I help! Mark brainly it would help<3
Selections 2, 3, 5, 6 are polynomials.
1 and 4 are not. The coefficients don't have to be integers, but the powers of the variables need to be positive integers. In 1, you have x^-1. in 4, you have x^(1/2).
The five-number summary of the box plot consists of the following values:
1) minimum
2) 1st quartile
3) median
4) 3rd quartile
5) maximum
The data between the first and third quartiles is: <span>b. 50% of the data is between the first and third quartiles </span>
Well your answer depends on what the initial number is.
example: the square root of 100 is 10. the square root of 144 is 12 and so on