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uranmaximum [27]
3 years ago
5

Match the system of equations to their solutions

Mathematics
1 answer:
I am Lyosha [343]3 years ago
6 0

Answer:

2x + y = 12 & x = 9 - 2y --- (x = 5, y = 2)

x + 3y = 16 & 2x - y = 11 --- (x = 7, y = 3)

y = 11 - 2x & 4x - 3y = -13 --- (x = 2, y = 7)

2x + y = 11 & x - 2y = -7 --- (x = 3, y = 5)

Step-by-step explanation:

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How many hours would someone who earns $7.50 per hour have to work to earn $116.25?
Goshia [24]
Here is your answer:

Need to divide the amount he wants to the amount he gets every hour:

116.25÷7.50=15.5 hours

Which mean he has to work 15 and a half hours

Your answer is...
15.5 or if rounded 16 hours! Hope this Helps!
5 0
2 years ago
Read 2 more answers
I need some help please
muminat
Answer: 113.0 ft (bottom right corner)

=====================================

Explanation:

The triangle has a horizontal leg of 220 ft and a vertical leg of x ft. We'll use the tangent rule to connect the opposite side and adjacent side

opposite side = x
adjacent side = 220
this is with the reference angle shown in the diagram

So,
tan(angle) = opposite/adjacent
tan(26) = x/220
220*tan(26) = x
x = 220*tan(26)
x = 107.301169 ... see note below
x = 107.3

Now that we know the approximate value of x, we add on 5.7 to get
x+5.7 = 107.3+5.7 = 113.0

note: make sure your calculator is in degree mode. The value is approximate to 6 decimal places

3 0
3 years ago
If and represent rational expressions and b0 and y0, what is true of their product? Select three options.
o-na [289]

Answer:

Their product will be rational Can I see the answer options?

Step-by-step explanation:

3 0
3 years ago
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A seagull flying in the air over water drops a crab from a height of 45 feet.The distance the crab is from the water as it falls
jonny [76]
For the seagull to catch the crab, h(t)=g(t) so:

-16t^2+45=-13t+23  add 16t^2 to both sides

45=16t^2-13t+23  subtract 45 from both sides

16t^2-13t-22=0  using the quadratic equation:

t=(13±√1577)/32, since t>0

t=(13+√1577)/32 seconds

t≈1.65 seconds (to nearest hundredth of a second)

And the height that this occurs using either original equation is:

h((13+√1577)/32)≈1.59 ft (to nearest hundredth of a foot)
7 0
3 years ago
A trough is 10 ft long and its ends have the shape of isosceles triangles that are 4 ft across at the top and have a height of 1
Anna11 [10]

Answer:

7.5 ft³/min

Step-by-step explanation:

Let x be the depth below the surface of the water. The height, h of the water is thus h = 10 - x.

Now, the volume of water V = Ah where A = area of isosceles base of trough = 1/2bh' where b = base of triangle = 4 ft and h' = height of triangle = 1 ft. So, A = 1/2 × 4 ft × 1 ft = 2 ft²

So, V = Ah = 2h = 2(10 - x)

The rate of change of volume is thus

dV/dt = d[2(10 - x)]/dt = -2dx/dt

Since dV/dt = 15 ft³/min,

dx/dt = -(dV/dt)/2 = -15 ft³/min ÷ 2 = -7.5 ft³/min

Since the height of the water is h = 10 - x, the rate at which the water level is rising is dh/dt = d[10 - x]/dt

= -dx/dt

= -(-7.5 ft³/min)

= 7.5 ft³/min

And the height at this point when x = 8 inches = 8 in × 1 ft/12 in  = 0.67 ft is h = (10 - 0.67) ft = 9.33 ft

7 0
2 years ago
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