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Try this:
1) note that weight of pure antifreeze before mixing and after mixing is the same. So, if 'x' is weight of pure antifreeze in 50% solution, it is possible to make up equation before mixing: 0.5x+0.2*90.
2) there are 0.2*90=18 gal. of pure antifreeze in the 20% solution. If 'x' gal. is the weight of pure antifreeze in 50% sol. and 18 gal. is the weight of pure antifreeze in 20% sol., it is possible to make up an equation after mixing: 0.4(x+18).
3) using the both parts: 0.5x+0.2*90=0.4(x+18) ⇒ x=54 gal. of <u>pure</u> weight.
4) to find 50% solution of 54 gal. pure weight just 54:0.5=108 gal.
Answer: 108 gal.
Answer:
3/20 or .15
Step-by-step explanation:
You need to find 3/5 of 1/4, so you need to multiply
3/5*1/4= 3/20
3/20 or .15
Answer:
A. O 5
Step-by-step explanation:
1830 ÷ 31 = 59.032258...
The first non-zero digit of the quotient is 5.
The answer is -4. Do you need to know why?
