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erica [24]
2 years ago
8

Which of these systems of equations would be best solved using the subtraction​ method?

Mathematics
1 answer:
Lynna [10]2 years ago
4 0

Answer:

Step-by-step explanation:

1. x+2y=6 or x=6-2y

3x-2y=2

3(6-2y)-2y=2

18-6y-2y=2

18-8y=2

-8y=-18+2

-8y=-16

y=-16/-8

y=2 ans.

x+2*2=6

x+4=6

x=6-4=2 ans.

Proof:

3*2-2*2=2

6-4=2

2=2

I leave the rest for you to practice with.

3. 4x+y=7

2x+5y=-1

 

5. 3x+2y=-2

6x-y=6

Solve the system using the elimination method. Show all your steps.

7. -3x+3y=3

3x+y=9 add.

---------------------------------

4y=12

y=12/4

y=3 ans.

3x+3=9

3x=9-3

3x=6

x=6/3

x=2 ans.

Proof:

-3*2+3*3=3

-6+9=3

3=3

I'll leave the rest for practice.

9. -5x+12y=20

x-2y=-6

11. 3x+2y=1

4x+ 6y= 7

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Answer:

30 units^2

Step-by-step explanation:

The area of a trapezoid is

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The scale is 2 units per line

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A = 1/2 ( 2+8) * 6

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The ratio of males to females in a cycling club is 5:3.
taurus [48]

Answer:

3/2

Step-by-step explanation:

The ratio of males to females in a cycling club is 5:3.

1/3 of the males are under 18

2/9 of the females are under 18

The fraction of the club members that are under 18 is calculated as:

Male: Female = Male/Female

We are told in the above question:

1/3 of the males are under 18

2/9 of the females are under 18

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6 0
3 years ago
Find the area of the trapezoid to the nearest tenth.
erica [24]

Answer:

2.2 metres squared

Step-by-step explanation:

We need to find the area of this trapezoid.

The area of a trapezoid is denoted by:

A=\frac{(b_1+b_2)h}{2}, where b_1 and b_2 are the parallel bases and h is the height

Here, we already know the lengths of the two bases; they are 0.9 metres and 2.3 metres. However, we need to find the length of the height.

Notice that one of the angles is marked 45 degrees. Let's draw a perpendicular line from top endpoint of the segment labelled 0.9 to the side labelled 2.3. We now have a 45-45-90 triangle with hypotenuse 2.0 metres. As one of such a triangle's properties, we can divide 2.0 by √2 to get the length of both legs:

2.0 ÷ √2 = √2 ≈ 1.414 ≈ 1.4

Thus, the height is h = 1.4 metres. Now plug all these values we know into the equation to find the area:

A=\frac{(b_1+b_2)h}{2}

A=\frac{(0.9+2.3)*1.4}{2}=2.2

The answer is thus 2.2 metres squared.

<em>~ an aesthetics lover</em>

8 0
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