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lapo4ka [179]
3 years ago
6

Identify and explain the four steps for solving a problem. Should any other factors be accounted for when solving a problem? Sho

uld any factors be accounted for when explaining how to solve a problem?
Mathematics
1 answer:
mihalych1998 [28]3 years ago
5 0
Step 1: simplify the equation by using the distributive property where applicable and combining like trems 
Step 2: Collect all the variables on one side by either adding or subtracting.
step 3:Using inverse operations for addition and subtraction can removecontants ,toget the vaiables and constants on opposite sides.
Step 4:Inverse operations, such as multiplying and dividing can be used to eliminate coefficients in front of variables to get the variables by themselves
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T=4U/E SOLVE FOR U please please please help please thank you
vlada-n [284]
TE/4 =U
Step by step
You multiply both sides by E to get rid of it then you have TE =4U and then u divide it by 4 and get TE/4 =U
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2 years ago
16x - 5y = -33<br> 16x + y = -51
timofeeve [1]
Use the elimination process
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olga2289 [7]

Step-by-step explanation:

You put them together to form a bigger number then break it down. sorry if it doesn't make sense.

Btw do you form the number if so I'll help just give the number and I'll break it down for you. :)

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What’s the difference quotient simplified
mihalych1998 [28]

\text{Use}\ (a+b)^3=a^3+3a^2b+3ab^2+b^3\\\\f(x+h)\to\text{exchange x to x + h}\\\\f(x)=x^3+3x\\\\f(x+h)=(x+h)^3+3(x+h)\\\\f(x+h)=x^3+3x^2h+3xh^2+h^3+3x+3h\\\\\dfrac{f(x+h)-f(x)}{h}=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-(x^3-3x)}{h}\\\\=\dfrac{x^3+3x^2h+3xh^2+h^3+3x+3h-x^3-3x}{h}\\\\=\dfrac{(x^3-x^3)+3x^2h+3xh^2+h^3+(3x-3x)+3h}{h}\\\\=\dfrac{3x^2h+3xh^2+h^3+3h}{h}\\\\=\dfrac{h(3x^2+3xh+h^2+3)}{h}\\\\=\boxed{3x^2+3xh+h^2+3}

7 0
3 years ago
Slope and rate of changes describe the same value true or false​
Anit [1.1K]

Answer:

True

Step-by-step explanation:

“Rate of change” means the same as “slope.” If you are asked to find the rate of change, use the slope formula or make a slope triangle.

8 0
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