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denpristay [2]
2 years ago
14

8cm 20cm What is the volume of this cylinder?

Mathematics
1 answer:
Firlakuza [10]2 years ago
8 0

Answer:

<u>4021.2386 cm ^3</u>

Step-by-step explanation:

V = πr2h = π·82·20 = 4021.2386 cm ^3

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3 0
3 years ago
What’s -6-25 divided by 5+5 ?
Inessa [10]

Answer:

-6

Step-by-step explanation:

6 0
3 years ago
An element with mass 970 grams decays by 27.7% per minute. How much of the element is remaining after 13 minutes, to the nearest
Mnenie [13.5K]
Basically, 27.7% of 970 is 268.69 grams, if 13 minutes so i’m pretty sure it’s 268.69 X 13 = 3492.97, it cannot be deduced from 970 unless it became −2522.97, is that the answer ur looking for?
6 0
2 years ago
HOW TO PUT 12/15 IN SIMPLEST FORM
mr_godi [17]

Answer:

4/5

Step-by-step explanation:

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4/5

5 0
3 years ago
let X represent the amount of time till the next student will arriv ein the library partking lot at the university. If we know t
AlekseyPX

Answer:

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 4 minutes

This means that m = 4, \mu = \frac{1}{4} = 0.25

Find the probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot:

This is:

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2)

In which

P(X \leq 132) = 1 - e^{-0.25*132} = 1

P(X \leq 2) = 1 - e^{-0.25*2} = 0.393469

P(2 \leq X \leq 132) = P(X \leq 132) - P(X \leq 2) = 1 - 0.393469 = 0.606531

0.606531 = 60.6531% probability that it will take between 2 and 132 minutes for the student to arrive at the library parking lot.

4 0
3 years ago
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