Answer:
The simple interest accumulated on a principal of $ 2,500 at a rate of 6.25% per year for 2.5 years is $ 390.63.
Step-by-step explanation:
Given
- Interest rate r = 6.5% = 0.065
- Time period = t = 2.5 years
To determine
Interest I = ?
Using the simple interest formula
I = Prt
substituting P = 2,500, r = 0.065 and t = 2.5
I = 2500 × 0.0625 × 2.5
I = 390.63
Thus,
I = $390.63
Therefore, the simple interest accumulated on a principal of $ 2,500 at a rate of 6.25% per year for 2.5 years is $ 390.63.
Answer:
The cost of the merchandise inventory of 30 units on Nov 30 = $700
Step-by-step explanation:
given,
Nov. 1 Inventory 20 units at $20
4 Sold 10 units
10 Purchased 30 units at $24
17 Sold 20 units
30 Purchased 10 units at $22
Units sold on 4th is out of Nov 1 inventory = (10 x 20)
= $200
30 units on November 30th cost is =
= 20 x $24 + 10 x $22
= $700
The cost of the merchandise inventory of 30 units on Nov 30 = $700
Multiply the percentage and hundred
Step-by-step explanation:
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Answer:
i know there's a lot of explanation. but it helps u for sure :)
Step-by-step explanation:
1)
![-7 \ and \ \frac{1}{3} = \frac{-7}{1} \ and \ \frac{1}{3}\\\\LCM \ of \ 1 \ and\ 3 = 3\\\\\frac{-21}{3} \ and \ \frac{1}{3}\\\\To \ find \ rational \ numbers \ between \ \frac{-21}{3} \ and \ \frac{1}{3} \ write \ any \ number \ between \ -21 \ and \ 1 \ with \ denominator \ 3. \\\\That \ is, \ \frac{-20}{3}, \frac{-19}{3}, \frac{-18}{3}.....](https://tex.z-dn.net/?f=-7%20%5C%20and%20%5C%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20%5Cfrac%7B-7%7D%7B1%7D%20%5C%20and%20%5C%20%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5CLCM%20%5C%20of%20%5C%201%20%5C%20and%5C%203%20%3D%203%5C%5C%5C%5C%5Cfrac%7B-21%7D%7B3%7D%20%5C%20and%20%5C%20%5Cfrac%7B1%7D%7B3%7D%5C%5C%5C%5CTo%20%5C%20find%20%5C%20rational%20%5C%20numbers%20%5C%20between%20%5C%20%5Cfrac%7B-21%7D%7B3%7D%20%5C%20and%20%5C%20%5Cfrac%7B1%7D%7B3%7D%20%5C%20write%20%5C%20any%20%5C%20number%20%5C%20between%20%5C%20-21%20%5C%20and%20%5C%201%20%5C%20with%20%5C%20denominator%20%5C%203.%20%5C%5C%5C%5CThat%20%5C%20is%2C%20%5C%20%20%5Cfrac%7B-20%7D%7B3%7D%2C%20%5Cfrac%7B-19%7D%7B3%7D%2C%20%5Cfrac%7B-18%7D%7B3%7D.....)
2)
![\frac{5}{9} \ and \ \frac{2}{3}\\\\Similarly \ take \ LCM \ of \ 9 \ and \ 3 = 9\\\\Since \ it \ is \ still \ complicated \ to \ find \ rational \ number \ between \ \frac{5}{9} \ and \ \frac{6}{9},](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B9%7D%20%5C%20and%20%5C%20%5Cfrac%7B2%7D%7B3%7D%5C%5C%5C%5CSimilarly%20%5C%20take%20%5C%20LCM%20%5C%20of%20%5C%209%20%5C%20and%20%5C%203%20%3D%209%5C%5C%5C%5CSince%20%5C%20it%20%5C%20is%20%5C%20still%20%5C%20complicated%20%5C%20to%20%5C%20find%20%5C%20rational%20%5C%20number%20%5C%20between%20%5C%20%5Cfrac%7B5%7D%7B9%7D%20%5C%20and%20%5C%20%5Cfrac%7B6%7D%7B9%7D%2C)
![We \ will \ multiply \ numerator \ and \ denominator\ by\ 10. \\\\Therefore\ \frac{5}{9} \ and \ \frac{6}{9} \ becomes \ \frac{50}{90} \ and \ \frac{60}{90}.](https://tex.z-dn.net/?f=We%20%5C%20will%20%5C%20multiply%20%20%5C%20numerator%20%5C%20and%20%5C%20denominator%5C%20by%5C%2010.%20%5C%5C%5C%5CTherefore%5C%20%20%5Cfrac%7B5%7D%7B9%7D%20%5C%20and%20%5C%20%5Cfrac%7B6%7D%7B9%7D%20%5C%20becomes%20%5C%20%5Cfrac%7B50%7D%7B90%7D%20%5C%20and%20%5C%20%20%5Cfrac%7B60%7D%7B90%7D.)
![Keeping \ denominator \ 90 \ write \ numbers \ from \ 50 \ to \ 60 \ in \ the\ numerator.\\\\That \ is , \frac{51}{90}, \frac{52}{90}, \frac{53}{90}, \frac{54}{90}, .\ .\ .](https://tex.z-dn.net/?f=Keeping%20%5C%20denominator%20%5C%2090%20%5C%20%20write%20%5C%20numbers%20%5C%20from%20%5C%20%2050%20%5C%20to%20%20%5C%2060%20%5C%20in%20%5C%20the%5C%20numerator.%5C%5C%5C%5CThat%20%5C%20is%20%2C%20%5Cfrac%7B51%7D%7B90%7D%2C%20%5Cfrac%7B52%7D%7B90%7D%2C%20%5Cfrac%7B53%7D%7B90%7D%2C%20%5Cfrac%7B54%7D%7B90%7D%2C%20.%5C%20%20.%5C%20%20.)
3)
![LCM \ of \ 5 \ and \ 7 = 35\\\\\frac{-2}{5} \ and \ \frac{-3}{7}\ becomes \ \frac{-14}{35} \ and \ \frac{-15}{35}\\\\Now \ multiply \ denominator \ and \ numerator \ by \ 10\\\\\frac{-140}{350} \ and \ \frac{-150}{350}.\\\\Rational \ numbers \ are \frac{-141}{350}, \frac{-142}{350}, \frac{-143}{350}, . \ . \ . \](https://tex.z-dn.net/?f=LCM%20%5C%20of%20%5C%205%20%5C%20and%20%5C%207%20%3D%2035%5C%5C%5C%5C%5Cfrac%7B-2%7D%7B5%7D%20%5C%20and%20%5C%20%5Cfrac%7B-3%7D%7B7%7D%5C%20%20becomes%20%5C%20%5Cfrac%7B-14%7D%7B35%7D%20%5C%20and%20%5C%20%5Cfrac%7B-15%7D%7B35%7D%5C%5C%5C%5CNow%20%5C%20multiply%20%5C%20denominator%20%5C%20and%20%5C%20numerator%20%5C%20by%20%5C%2010%5C%5C%5C%5C%5Cfrac%7B-140%7D%7B350%7D%20%5C%20and%20%5C%20%5Cfrac%7B-150%7D%7B350%7D.%5C%5C%5C%5CRational%20%5C%20numbers%20%20%5C%20are%20%5Cfrac%7B-141%7D%7B350%7D%2C%20%5Cfrac%7B-142%7D%7B350%7D%2C%20%5Cfrac%7B-143%7D%7B350%7D%2C%20.%20%5C%20.%20%5C%20.%20%5C)
Tip :
1. Make the denominator same.
2. Multiply numerator and denominator by 10 , 100 or 1000
3. Just write the natural numbers between the 2 numerators keeping denominator same.