Question

If enrollment increases by approximately the same

Answer 1

Given:

The enrollment increases by approximately the same percentage between 2000 and 2010 as it decreased between 1950 and 1960.

To find:

The expected enrollment in 2010.

Solution:

Percentage decrease formula:

$\%\text{ decrease}=\dfrac{\text{Initial value - New value}}{\text{Initial value}}\times 100$

The percentage decrease in between 1950 and 1960 is:

$\%\text{ decrease}=\dfrac{4-3.5}{4}\times 100$

$\%\text{ decrease}=\dfrac{0.5}{4}\times 100$

$\%\text{ decrease}=\dfrac{50}{4}$

$\%\text{ decrease}=12.5$

The enrollment decreased by 12.5% between 1950 and 1960. So, the enrollment increases by 12.5% between 2000 and 2010.

The expected enrollment in 2010 is:

$\text{Expected enrollment}=7+\dfrac{12.5}{100}\times 7$

$\text{Expected enrollment}=7+0.875$

$\text{Expected enrollment}=7.875$

Therefore, the expected enrollment in 2010 is 7.875 thousands.