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sergejj [24]
3 years ago
8

Which one is it .....

Mathematics
2 answers:
lisov135 [29]3 years ago
7 0

Answer:

D) n/3 - 7

Step-by-step explanation:

n/3 - 7

7 is subtracted (so it's behind) and the quotient (fraction) of n and 3

zubka84 [21]3 years ago
6 0

Answer:

D) n/3 - 7

Step-by-step explanation:

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\int_1^{2}\frac{dz}{(z-1)^2}=\left[-\frac{1}{z-1}\right]_1^2\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\frac{1}{1-1}+\frac{1}{2-1}\\\\\int_1^{2}\frac{dz}{(z-1)^2}=-\infty\\

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\int_1^{\infty} \frac{dx}{\sqrt{x}}=\left[2\sqrt{x}\right]_1^{\infty}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=2\sqrt{\infty}-2\sqrt{1}\\\\\int_1^{\infty} \frac{dx}{\sqrt{x}}=\infty\\

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4 0
3 years ago
The amounts a soft drink machine is designed to dispense for each drink are normally distributed, with a mean of 12.1 fluid ounc
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Answer:

\mu = 12.1\\\sigma = 0.3

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z=\frac{x-\mu}{\sigma}

z=\frac{11.6-12.1}{0.3}

z=-1.67

x= 11.9

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z=\frac{x-\mu}{\sigma}

z=\frac{11.9-12.1}{0.3}

z=-0.67

We are supposed to find P(11.6<x<11.9)

So, P(11.6<x<11.9)= P(x<11.9)-P(x<11.6)

P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

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P(-1.67<z<-0.67)= P(z<-0.67)-P(z<-1.67)

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P(z>1.67)=1-P(z<1.67)

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P(z>1.67)=0.0475

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d) Is the drink containing more than 12.6 fluid ounces an unusual event?

Since p value is less than  alpha (0.05)

Answer = No, because the probability that a drink containing more than 12.6 fluid ounces is less than 0.05, this event is not unusual.

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