Which one is it .....

Which expression is equivalent to<br>o ooo

k0ka [10]

Answer:

a

Step-by-step explanation:

becuase you distribute the numbers

5 0

3 years ago

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TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin

yarga [219]

Answer:

a)

The 99% confidence interval for the proportion of all adult Americans who watched streamed programming up to that point in time is (0.5336, 0.5864). This means that we are 99% sure that the true proportion of all adult Americans who watched streamed programming up to that point in time is between these two values.

b)

A sample size of 664 is required.

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

A poll reported that 56% of 2348 American adults surveyed said they have watched digitally streamed TV programming on some type of device.

This means that $\pi = 0.56, n = 2348$

99% confidence level

So $\alpha = 0.01$ , z is the value of Z that has a p-value of $1 - \frac{0.01}{2} = 2.575$ , so $Z = 2.575$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.56 - 2.575\sqrt{\frac{0.56*0.44}{2348}} = 0.5336$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.56 + 2.575\sqrt{\frac{0.56*0.44}{2348}} = 0.5864$

The 99% confidence interval for the proportion of all adult Americans who watched streamed programming up to that point in time is (0.5336, 0.5864). This means that we are 99% sure that the true proportion of all adult Americans who watched streamed programming up to that point in time is between these two values.

b. What sample size would be required for the width of a 99% CI to be at most .05 irrespective of the value P?

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

This sample size is given by n, with $M = 0.05$ and $\pi = 0.5$ .

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.05 = 2.575\sqrt{\frac{0.5*0.5}{n}}$

$0.05\sqrt{n} = 2.575*0.5$

Dividing both sides by 0.05.

$\sqrt{n} = 2.575*10$

$(\sqrt{n})^2 = (2.575*10)^2$

$n = 663.1$

Rounding up:

A sample size of 664 is required.

7 0

3 years ago

If -2x + 3 = 7 and 3x + 1 = 5 + y , what is the value of y

Lubov Fominskaja [6]

Answer: -10

Step-by-step explanation:

4 0

3 years ago

Sharon's town has 790 households. She wanted to find out how many of them turn out the lights on Halloween each year to avoid vi

MAXImum [283]

We have been given that the total number of households she surveyed = 150

Now, out of 150, 35 of them said they turn out the lights each year on Halloween.

Now, in order to find the percentage of households that turn out the lights each year on Halloween, we will divide 35 by 150 and then multiply the result with 10.

Thus, we the required percentage is given by

$\frac{35}{150} \times 100\\
\\
=\frac{7}{30} \times 100\\
\\
=\frac{70}{3} \\
\\
=23.33\%$

Therefore, to nearest percent is 23%.

Hence, the estimated population proportion of households that turn out the lights each year on Halloween is 23%

6 0

3 years ago

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Which of the following equations is equivalent to 3(2p + 4) – (3p – 4) = 43?

kupik [55]

I just solved it for you and the answer i got was D

4 0

2 years ago