Point a,b and are collinear and b bet a,c if ab=48,ab=2x +2,and bc=3x+6 what is bc?

The difference between two numbers is 7. The sum of twice the larger number and three times the smaller number is 19.

Alex17521 [72]

Answer:

x= 8 y= 1

Step-by-step explanation:

First, you identify your variables:

x= larger number

y= smaller number

Second, you find your equations:

x - y = 7

2x + 3y = 19

Third, (I used the substitution method) you make "y" by itself for the 1st equation.

y = x - 7

2x + 3y = 19

Then, you plug in the 1st equation for "y" in the 2nd equation

2x + 3(x - 7) = 19

Then, you distribute and simplify.

2x + 3x - 21 = 19

5x - 21 = 19

5x = 40

x = 8

Finally, you plug in the variable you found ( x ) into one of the equations and solve,

8 - y = 7

- y = -1

y = 1

6 0

3 years ago

Write a eclamamatory sententece <br>about a mother

shusha [124]

Answer:

*exclamatory* The mother was screaming in agony while giving birth!

Step-by-step explanation:

Im using the exclamation mark, there for its an exlamatory in a sentace about a mother.

6 0

3 years ago

Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.

Leviafan [203]

Answer:

Option D. 3.73

Step-by-step explanation:

we know that

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

and

$sin^{2}(\alpha)+cos^{2}(\alpha)=1$

step 1

Find cos(X)

we have

$sin(x)=\frac{1}{2}$

we know that

$sin^{2}(x)+cos^{2}(x)=1$

substitute

$(\frac{1}{2})^{2}+cos^{2}(x)=1$

$cos^{2}(x)=1-\frac{1}{4}$

$cos^{2}(x)=\frac{3}{4}$

$cos(x)=\frac{\sqrt{3}}{2}$

step 2

Find tan(x)

$tan(x)=sin(x)/cos(x)$

substitute

$tan(x)=1/\sqrt{3}$

step 3

Find sin(y)

we have

$cos(y)=\frac{\sqrt{2}}{2}$

we know that

$sin^{2}(y)+cos^{2}(y)=1$

substitute

$sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1$

$sin^{2}(y)=1-\frac{2}{4}$

$sin^{2}(y)=\frac{2}{4}$

$sin(y)=\frac{\sqrt{2}}{2}$

step 4

Find tan(y)

$tan(y)=sin(y)/cos(y)$

substitute

$tan(y)=1$

step 5

Find tan(x+y)

$tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}$

substitute

$tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73$

7 0

3 years ago

The frequency of vibrations of a vibrating violin string isgiven by

arlik [135]

Answer:a. [tex] $f\propto L$ [\tex]

b. [tex] f \propto \sqrt{T} [\tex]

c. [tex] f \propto \frac{1}{\sqrt{P}} [\tex]

I. Decrease in length increases leads to increase in pitch.

II. Increase in tension leads to increase in pitch.

III. Increase in linear density reduces the pitch

Step-by-step explanation: I. Since the frequency is inversely proportional to the length increase in length leads to decrease in frequency likewise decrease in length leads to increase in frequency.

II. Since the frequency is directly proportional to the square root of the tension increase in tension leads to increase in frequency likewise decrease in tension leads to decrease in frequency.

III.since the frequency is inversely proportional to the square root of the linear density so increase in linear density leads to decrease in frequency and likewise decrease in linear density leads to increase in frequency.

7 0

3 years ago

In a call center that stays open all the time, calls arrive as a poisson process with a mean rate of 0.3 complaints per hour.(a)

DENIUS [597]

The probability the 51st call arriaves within 150hours is 0.0431, the probability the next call arrives within the next 2 hours 0.5488, the probability the sum of these 50 numbers is less than 356 is 0.4165.

Data;