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GREYUIT [131]
3 years ago
11

A local eat-in pizza restaurant wants to investigate the possibility of starting to deliver pizzas. The owner of the store has d

etermined that home delivery will be successful only if the average time spent on a delivery does not exceed 38 minutes. The owner has randomly selected 27 customers and delivered pizzas to their homes. What hypotheses should the owner test to demonstrate that the pizza delivery will not be successful
Mathematics
1 answer:
Alinara [238K]3 years ago
4 0

Answer:

Read step by step explanation

Step-by-step explanation:

The owner already knows that the limit for the average time delivered pizzas is 38 minutes. So we conclude

1.-The resulting mean from sample data ( x ) ( 27 customers) need to be smaller than 38 minutes, any value of sample above 38 minutes means more time for the delivery action and will indicate a failure for the future project

2.-As sample size is smaller than 30 the test has to be  t-student one tail test to the left

Test hypothesis

Null hypothesis                       H₀                  x  = 38

Alternative hypothesis           Hₐ                  x  <  38

We should test at a significance level α  = 0,05       (α = 5%)

If the result of the test is to accept  H₀  delivery project won´t be implemented, if on the other hand, H₀ is rejected then in the condition of the alternative hypothesis we accept Hₐ the sample indicates that we have a smaller average time than 38 minutes.

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Need help ASAP please and thank you
Gemiola [76]
The 3rd one I think
5 0
3 years ago
Use the digits 1,3,4,and 7 to create two whole numbers whose product is estimated to be about 600
blagie [28]
34 x 17  (round the 2 numbers)
30 x 20
   600

Also, 34 x 17 = 578, which rounds to 600


The answer is 34 and 17

7 0
3 years ago
Read 2 more answers
Please answer and show steps please show steps please show steps 10 points
natali 33 [55]

Answer:

it is C 10

Step-by-step explanation:

 If the positions are distinct, as in executive offices, then P(9, 5). 

P(9, 5) = 9!/(9 - 5)! = 15120 

If the positions are equivalent, such as seats in a legislative body, then C(9, 5). 

C(9, 5) = 9!/[(9 - 5)!(5!)] = 126

Assuming the five positions are unique in their duties and responsibilities (i.e. order matters): position 1 has 9 candidates to choose from, position 2 has 8, position 3 has 7, and so on. Otherwise, if you're talking about 5 distinct but duplicate positions - meaning their responsibilities are the same but 5 people are required to carry them out - you need to divide the previous total number of possibilities by the number of ways those possibilities could have been reordered.

8 0
3 years ago
A student has earned scores of 87, 81, and 88 on the first 3 of 4 tests. If the student wants an average (arithmetic mean) of ex
Juli2301 [7.4K]
To find an average you take the numbers to be averaged and add them together then You take the number and divide it by the number of numbers, in this case 4, and that gives you the average.
on this problem you want to do the opposite. you know the average she wants, an 87, so you multiply it by 4. 87*4=348. then you add the three numbers you have (88,81 and 87) and you get 256.
then you subtract 256 from 348 and you get 92. 92 is your answer to check just add 87+81+88+92=348
348/4=87
87 was the average she wanted.
Hope this helped! good luck :)
4 0
3 years ago
The difference between the two numbers is 48. The ratio of the two numbers is 7:3. What are the two numbers?
OlgaM077 [116]

Let the bigger no. be X and the smaller no. be Y

X-Y=48

7-3=4

48÷4=12

X=12×7=84

Y=12×3=36

6 0
3 years ago
Read 2 more answers
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