The data set below represents the ages of 11 kids in an after-school program. 10, 11, 8, 7, 6, 10, 7, 10, 9, 9, 12 Which box plo
Andreas93 [3]
Answer:
This is the answer because you need to find mean median mode range, first quertile, third quartile
Whisker plot below
Step-by-step explanation:
Mean (Average) 9
Median 9
Range 6
Mode 10, appeared 3 times
Geometric Mean 8.8206311297046
Largest 12
Smallest 6
Sum 99
Count 11
■ 1st quartile (lower quartile) = 7.5
■ 2st quartile (median) = 9
■ 3st quartile (upper quartile) = 10
Answer:
answer is -1 according to calculation
Answer:
36⁄125 or if we are talking about the lowest term it is 9
/3125
Step-by-step explanation:
Step 1: 0.288 = 288⁄1000
Step 2: Simplify 288⁄1000 = 36⁄125 Percent" or "%" means "out of 100" or "per 100",
<em>Or for the lowest term:</em>
Therefore 0.288% can be written as
0.288
100
.
Next, we can multiply by
1
in the form of
1000
1000
to eliminate the decimal in the numerator:
1000
1000
×
0.288
100
⇒
1000
×
0.288
1000
×
100
⇒
288
100000
.
We can now reduce the fraction as:
288
100000
⇒
32
×
9
32
×
3125
⇒
32
×
9
32
×
3125
⇒
9
3125
.
X=0
-23 = x - 23
Step 1 cancel equal terms on both sides of the equation
0=x
Step 2 swap the sides of the equation
x=0
Answer:
r = 1/2
c1 = 3/4
c2 = 27/64
c3 = 405/1408
Step-by-step explanation:
Find the solution of 4x2y′′−4x2y′+y=0,x>04x2y″−4x2y′+y=0,x>0 of the form y1=xr(1+c1x+c2x2+c3x3+⋯)
r = 1/2
c1 = 3/4
c2 = 27/64
c3 = 405/1408
The solution is attached.
