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Leona [35]
3 years ago
10

You move left 3 units. You end at -4, -3. Where did you start?

Mathematics
1 answer:
Andrews [41]3 years ago
5 0

Answer:

(-4+3, -3) = (-1,-3)

Step-by-step explanation:

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If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .​
Tems11 [23]

Divide through everything by <em>b</em> :

\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}

Since <em>a/b</em> < <em>c/d</em>, it follows that

\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}

Multiply through everything on the right side by <em>b/d</em> to get

\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) < <em>c/d</em>.

For the other side, you can do something similar and divide through everything by <em>d</em> :

\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}

and <em>a/b</em> < <em>c/d</em> tells us that

\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}

Then

\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab

and so (<em>a</em> + <em>c</em>)/(<em>b</em> + <em>d</em>) > <em>a/b</em>.

Then together we get the desired inequality.

5 0
3 years ago
Please answer and explain
sashaice [31]
8=2*2*2=2^3
32=2*2*2*2*2=2^5
<span>[8^(2/3)] / [32^(2/5)] = [</span>(2^3)^(2/3)] / [(2^5)^(2/5)] =
= [2^(3*2/3)] / [2^(5*2/5)]= [2^2] / [2^2] = 4/4 = 1
Answer: 1
4 0
2 years ago
P/9 - 1 &lt; -2 ...<br> Solve for p
love history [14]

Step-by-step explanation:

first collect terms, while the < remains unchange

<u>P</u><u> </u><u> </u>< 1-2

9

cross examine and get the answer

<u>P</u><u> </u>< <u>-</u><u>1</u>

9 1

<em>P</em><em> </em><em>=</em><em> </em><em>-</em><em>9</em>

7 0
3 years ago
Express the product in simplest form.
Romashka [77]
\frac{8}{2x+8} *  \frac{ x^{2}-16 }{4}

1. Cross cancel
\frac{4}{2x+8}* \frac{ x^{2} -16}{1}

2. Multiply numerators
4*x²-16 = 4x²-64

3. Multiply denominators
2x+8*1 = 2x+8

\frac{4 x^{2} -64}{2x+8}

4. Divide
\frac{4 x^{2} -64}{2x+8} = 2x-8

5. Simplify
2(x-4)

Answer is 2(x - 4)
4 0
3 years ago
ABC has side lengths that are each equal to
likoan [24]

Answer:

Step-by-step explanation:no

6 0
3 years ago
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