Answer:
5 1/4
Step-by-step explanation:
First you have to figure out how much a video game costs and how much a used one costs
Then you plug in the costs of the video games into Janets equation 120=3x+y
(x= video games and y=used video games)
Then you subtract the cost of video games from 120 and then divide that answer by the cost of used video games and that should give you how many used video games she can get
A. Mr. Kent interviewed the 54 students as they are going to leave the school, it is not considered to be a random sample. It is because a random sample is when a set is taken from a population. Mr. Kent interviewed the 54 who are going to leave, meaning, he didn't take a set out of that 54, he took all of them. So it is not a random sample.
b. The question that Mr. Kent asked is considered to be a leading question, so it does not seem biased.
c. If there are 54 respondents.
51 = yes, the rest is no.
= 54 - 51 = 3
= 3 is now divided to 54 = 3/54
= giving an answer of 0.0555
= 0.0555 x 100
= 5.6%
= The percent of responses that says 'no' is 5.6%
Find ing the common denominator would make it 10.
for 1/2 to get to 10 you have to multiply by 5
1/2x5= 5/10
then you have to convert 2/5 to get the denominator to be 10
so you multiply 2/5 by 2
2/5x2= 4/10
5/10 is greater than 4/10
Problem 2
Part (a)
The 3D shape formed when rotating around the y axis forms a pencil tip
The shape formed when rotating around the x axis is a truncated cone turned on its side.
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Part (b)
Check out the two diagrams below.
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Problem 3
Answer: Choice A and Choice C
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Explanation:
Think of stacks of coins. Let's say we had 2 stacks of 10 quarters each. The quarters are identical, so they must produce identical volumes. Those sub-volumes then add up to the same volume for each stack. Now imagine one stack is perfectly aligned and the other stack is a bit crooked. Has the volume changed for the crooked stack? No, it hasn't. We're still dealing with the same amount of coins and they yield the same volume.
For more information, check out Cavalieri's Principle.
With all that in mind, this leads us to choice C. If the bases are the same, and so are the heights, then we must be dealing with the same volumes.
On the other hand, if one base is wider (while the heights are still equal) then the wider based block is going to have more volume. This leads us to choice A.