3x-2<4 what is the solution set for this equality?
1 answer:
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Answer:
76.
Step-by-step explanation:
It is given that N is a 2-digit number.
Last two digits of N^2 is the same as N.
We know that, a number is even if it ends with 0,2,4,6,8.
If 0 is in end then we get two zeros in the square of that number.
It is clear that, number should ends with 6 to get the same number at the end.
It is clear that last two digits of (76)^2 is the same as 76.
Therefore, the required number is 76.