Can you help me with number 4 A-D plz

Mathematics

1 answer:

Flauer [41]3 years ago

5 0

You have to label it but try 1 and 1/4, -1 and 1/4,2, and -2

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a cell phone company found that 15 of their phones sold in June were defective. The company sold 250 phone in June. How many of

larisa [96]

Write and solve an equation of ratios, as follows:

15 250

----- = ------- = 10/12.

x 300

Then 15(12) = 10x, and x = 18. The company could well predict that 18 out of the 300 phones it sells in July will be defective, based upon past history.

6 0

3 years ago

Everyone needs to get off of social and help us -_-

JulsSmile [24]

(x+2)(x+8)(x+k)=x^3+9x^2+6x-16

(x^2+10x+16)(x+k)=x^3+9x^2+6x-16

x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16

kx^2+10kx+16k=-x^2-10x-16

k(x^2+10x+16)=-x^2-10x-16

k=(-x^2-10x-16)/(x^2+10x+16)

k=-1

so the width is (x-1)

7 0

3 years ago

You want to obtain a sample to estimate a population proportion. At this point in time, you have no reasonable preliminary estim

pogonyaev

Answer:

$n=\frac{0.5(1-0.5)}{(\frac{0.025}{1.28})^2}=655.36$

And rounded up we have that n=656

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 80% of confidence, our significance level would be given by $\alpha=1-0.80=0.20$ and $\alpha/2 =0.10$ . And the critical value would be given by:

$z_{\alpha/2}=\pm 1.28$

Solution to the problem

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

Since we don't have prior info for the proportion of interest we can use $\hat p=0.5$ as estimator. And on this case we have that $ME =\pm 0.025$ and we are interested in order to find the value of n, if we solve n from equation (a) we got: