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Gwar [14]
3 years ago
10

Which shows the equation below written in the form ax2 + bx+c = 0? x*2+7x+ 9 = 3

Mathematics
2 answers:
Gala2k [10]3 years ago
8 0

Hi!

x² + 7x + 9 = 3

x² + 7x + 9 - 3 = 0

<u>x²</u><u> </u><u>+</u><u> </u><u>7</u><u>x</u><u> </u><u>+</u><u> </u><u>6</u><u> </u><u>=</u><u> </u><u>0</u>

eduard3 years ago
6 0

Answer:

x^2+7x+ 6 = 0

Step-by-step explanation:

x^2+7x+ 9 = 3

Subtract 3 from each side

x^2+7x+ 9-3 = 3-3

x^2+7x+ 6 = 0

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4 years ago
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Step-by-step explanation:

Step 1:

First, we need to calculate the areas of both circles.

The area of a circle = \pi r^{2} where r is the radius of the circle.

The inner-circle has a radius of 4 cm.

The area of the inner circle= \pi (4^{2})= 3.1415(16) = 50.264.

The outer circle has an inner radius of 4 cm and an outer radius of 8 cm.

So its area is \pi (R^{2} -r^{2} ) where R is the outer radius and r is the inner radius.

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Step 2:

To find the probability of an event we divide the number of favorable outcomes by the total number of outcomes.

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= 50.264+150.792 = 201.056 square cm.

The number of favorable outcomes is the area of the outer circle i.e. 150.792 square cm.

The probability of the rice falling in the outer circle =\frac{150.792}{201.056} = \frac{3}{4} = 75 \%.

7 0
3 years ago
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