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Fudgin [204]
3 years ago
10

Plsssssssssssssssssssssssssssssss help

Mathematics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

<h2><em>X=</em><em>1</em><em>6</em><em>6</em><em>°</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em><</em><em>ABE</em><em>+</em><em><</em><em>ABC</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em><</em><em>ABE</em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>9</em><em>7</em>

<em><</em><em>ABE</em><em>=</em><em>8</em><em>3</em><em>°</em>

<em><</em><em>ABC</em><em>=</em><em><</em><em>ACB</em><em>=</em><em>8</em><em>3</em><em>°</em>

<em><</em><em>ABC</em><em>+</em><em><</em><em>ACB</em><em>+</em><em><</em><em>CAB</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em><</em><em>CAB</em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>8</em><em>3</em><em>-</em><em>8</em><em>3</em>

<em><</em><em>CAB</em><em>=</em><em>1</em><em>4</em>

<em><</em><em>DAC</em><em>+</em><em><</em><em>CAB</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em><</em><em>DAC</em><em>+</em><em>1</em><em>4</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em><</em><em>DAC</em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>1</em><em>4</em>

<em><</em><em>DAC</em><em>(</em><em>X</em><em>)</em><em>=</em><em>1</em><em>6</em><em>6</em><em>°</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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In this problem, we have that:

\mu = 4.9, \sigma = 1.4

(a) the thickness is less than 3.0 mm

This is the pvalue of Z when X = 3.

Z = \frac{X - \mu}{\sigma}

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(b) the thickness is more than 7.0 mm

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1 - 0.9332 = 0.0668

0.0668 = 6.68% probability that the thickness is more than 7.0 mm

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