Ask question

Ask question

All categories

4 years ago

10

Plsssssssssssssssssssssssssssssss help

1 answer:

Semenov [28]4 years ago

7 0

Answer:

<h2><em>X=</em><em>1</em><em>6</em><em>6</em><em>°</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em><</em><em>ABE</em><em>+</em><em><</em><em>ABC</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em><</em><em>ABE</em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>9</em><em>7</em>

<em><</em><em>ABE</em><em>=</em><em>8</em><em>3</em><em>°</em>

<em><</em><em>ABC</em><em>=</em><em><</em><em>ACB</em><em>=</em><em>8</em><em>3</em><em>°</em>

<em><</em><em>ABC</em><em>+</em><em><</em><em>ACB</em><em>+</em><em><</em><em>CAB</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em><</em><em>CAB</em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>8</em><em>3</em><em>-</em><em>8</em><em>3</em>

<em><</em><em>CAB</em><em>=</em><em>1</em><em>4</em>

<em><</em><em>DAC</em><em>+</em><em><</em><em>CAB</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em><</em><em>DAC</em><em>+</em><em>1</em><em>4</em><em>=</em><em>1</em><em>8</em><em>0</em>

<em><</em><em>DAC</em><em>=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>1</em><em>4</em>

<em><</em><em>DAC</em><em>(</em><em>X</em><em>)</em><em>=</em><em>1</em><em>6</em><em>6</em><em>°</em>

<em>Hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

You might be interested in

Plz help urgent question below

zhannawk [14.2K]

A is the answer. Hope this helps

6 0

3 years ago

From the top make it drop that's a _____?

olga nikolaevna [1]

Answer:

January

February

march

April

may

June

jAsOn DeRuLo

3 0

4 years ago

Find the equation of the line with the given properties: passes<br> through (0,-9) and (-2,-9).

irga5000 [103]

Answer:

I WRITE THE STEPS

Step-by-step explanation:

Find the Equation of a Line Given That You Know a Point on the Line And Its Slope. The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept. If you a point that a line passes through, and its slope, this page will show you how to find the equation of the line.

8 0

3 years ago

A politician claims that 20% of the millions of votes cast for his opponent are fraudulent. To test this claim, an investigator

Elis [28]

Answer:

"0.0125" is the right solution.

Step-by-step explanation:

The given values are:

Random sample,

n = 90

Claims,

p = 20%

or,

= 0.20

By using normal approximation, we get

⇒ $\mu = np$

On substituting the values, we get

⇒ $=90\times 0.20$

⇒ $=18$

Now,

The standard deviation will be:

⇒ $\sigma=\sqrt{np(1-p)}$

On putting the above given values, we get

⇒ $=\sqrt{90\times 0.20\times (1-0.20)}$

⇒ $=\sqrt{18\times 0.8}$

⇒ $=\sqrt{14.4}$

⇒ $=3.7947$

hence,

By using the continuity correction or the z-table, we get

⇒ $P(x < 10) = P(x < 9.5)$

⇒ $P(x < 10) = P(\frac{x-\mu}{\sigma} -\frac{9.5-18}{3.7947} )$

⇒ $P(x < 10) = P(Z < -2.24)$

From table,

⇒ $P(x < 10) = 0.0125$

7 0

3 years ago

Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b

Elenna [48]

Answer:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Step-by-step explanation:

We want to verify the identity:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }$

Collect LCM

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }$

We simplify the RHS to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}$

We rationalize to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}$

We expand to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}$

Factor negative one in the denominator:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}$

Apply the Pythagoras Property to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}$

Simplify to get:

$\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}$

Or

$\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}$

Divide both the numerator and denominator by sin x

$\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}$

This finally gives:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

8 0

3 years ago