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3 years ago

Plsssssssssssssssssssssssssssssss help

Mathematics

1 answer:

Semenov [28]3 years ago

7 0

Answer:

Solution,

<ABE+<ABC=180

<ABE=180-97

<ABE=83°

<ABC=<ACB=83°

<ABC+<ACB+<CAB=180

<CAB=180-83-83

<CAB=14

<DAC+<CAB=180

<DAC+14=180

<DAC=180-14

<DAC(X)=166°

Hope this helps...

Good luck on your assignment...

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8. A triangle has sides with lengths of 6, 8, and 10 units, and a square has a

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Difference between the area of the triangle and square is 25

Step-by-step explanation:

Step 1: Find the area of the triangle given its 3 sides using the Heron's formula.

Area of the triangle = $\sqrt{s (s-a)(s-b)(s-c)}$ where s = $\frac{a + b + c}{2}$

⇒ s = (6 + 8 + 10)/2 = 24/2 = 12

$\sqrt{s(s-a)(s-b)(s-c)}$ = $\sqrt{12(12-6)(12-8)(12-10)}$

= $\sqrt{12(6)(4)(2)}$ = $\sqrt{576}$ = 24 sq. units

Step 2: Find the area of the square with perimeter = 28 units.

Perimeter of the square = 4 × side = 28

⇒ Side of the square = 28/4 = 7 units

⇒ Area of the square = (side)² = 7² = 49 sq. units

Step 3: Find the difference between the area of the square and triangle.

Difference = 49 - 24 = 25

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2 years ago

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2. Tuesday
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2 years ago

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Kiley had a piece of bamboo skewer that measured 14Three-fifths inches long. She wanted to cut it into toothpicks that were each

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Answer:

4 toothpicks.

Step-by-step explanation:

We have been given that Kiley had a piece of bamboo skewer that measured 14 3/5 inches long. She wanted to cut it into toothpicks that were each 3 1/5 inches long.

To find the number of toothpicks that Kiley can make from bamboo skewer, we need to divide the length of skewer by length of each toothpick.

Total number of toothpicks = 14 3/5 ÷ 3 1/5

First of all, we will convert our given mixed fractions into improper fractions as:

Total number of toothpicks = 73/5 ÷ 16/5

Dividing a fraction by another fraction is same as multiplying the 1st fraction by the reciprocal of 2nd fraction.

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2 years ago

A university researcher wants to estimate the mean number of novels that seniors read during their time in college. An exit surv

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Answer:

Population mean = 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

Step-by-step explanation:

Given - A university researcher wants to estimate the mean number

of novels that seniors read during their time in college. An exit

survey was conducted with a random sample of 9 seniors. The

sample mean was 7 novels with standard deviation 2.29 novels.

To find - Assuming that all conditions for conducting inference have

been met, which of the following is a 94.645% confidence

interval for the population mean number of novels read by

all seniors?

Proof -

Given that,

Mean ,x⁻ = 7

Standard deviation, s = 2.29

Size, n = 9

Now,

Degrees of freedom = df

= n - 1

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⇒Degrees of freedom = 8

Now,

At 94.645% confidence level

α = 1 - 94.645%

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=0.05355 ≈ 0.05

⇒α = 0.5

Now,

$\frac{\alpha}{2} = \frac{0.05}{2}$

= 0.025

Then,

$t_{\frac{\alpha}{2}, df }$ = 2.306

∴ we get

Population mean = x⁻ ± $t_{\frac{\alpha}{2}, df }$ × $\frac{s}{\sqrt{n} }$

= 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

⇒Population mean = 7 ± 2.306 × $\frac{2.29}{\sqrt{9} }$

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Answer:

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