Situation #3: Jamie can type 243 words in 3 minutes. How many words can she type in 10 minutes?

Mathematics

2 answers:

GrogVix [38]2 years ago

7 0

I ain’t never seen two pretty best friends

Ratling [72]2 years ago

3 0

Answer:

810 words

Step-by-step explanation:

243 words per 3 minutes

243/3 to get 81 words per minute

81 times 10 = 810

You might be interested in

Can someone pleaseeee help and if you’re correct i’ll give brainliest

deff fn [24]

Answer:

The answer should be 13.

8 0

2 years ago

Read 2 more answers

Solve for x e^2x=2.6

vesna_86 [32]

Answer:

Solve for

by simplifying both sides of the equation, then isolating the variable.

≈

0.25181781

Step-by-step explanation:

8 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :