In March it rained 8.23 inches. It rained 5.96 inches less in April than in March.
1 answer:
You might be interested in
Answer:
942
Step-by-step explanation :
so your d is 300 so your r = 300/2= 150
a=3.14*r*r= 3.14*150*150= 70650
c= 3.14*d= 3.14*300= 942
_________________________________________________
OR
The curved surface area of solid cylinder is
As we are given that:
Diameter of solid cylinder = 8 cm
Length or Height o solid cylinder = 140 cm
Formula used to calculate the curved surface area of cylinder is:2n x h
Curved surface area of cylinder =2r x h
where,
r = radius of cylinder
h = height or length of cylinder
Radius of cylinder = daimeter
Now putting all the given values in above formula, we get:
Curved surface area of cylinder = 2x 22/7 x 140cm
Curved surface area of cylinder =
Therefore, the curved surface area of solid cylinder is3520cm^{2}
Answer:
a)
b)
c)
With a frequency of 4
d)
<u>e)</u>
And we can find the limits without any outliers using two deviations from the mean and we got:
And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case
Step-by-step explanation:
We have the following data set given:
49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000
Part a
The mean can be calculated with this formula:
Replacing we got:
Part b
Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:
Part c
The mode is the most repeated value in the sample and for this case is:
With a frequency of 4
Part d
The midrange for this case is defined as:
Part e
For this case we can calculate the deviation given by:
And replacing we got:
And we can find the limits without any outliers using two deviations from the mean and we got:
And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case