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JulsSmile [24]
3 years ago
6

You can prove relationships between the corresponding parts of of two triangles once you have provided that the triangles are? A

-congruent. B-similar. C-equal. D-diffrent.
Mathematics
1 answer:
tankabanditka [31]3 years ago
8 0

Answer:

If two objects are congruent, then they are also similar.

Step-by-step explanation:

Congruent triangles have both the same shape and the same size. In the figure below, triangles , A, B, C,  , D, E, F,  are congruent; they have the same angle measures and the same side lengths.

Similar triangles have the same shape, but not necessarily the same size. In the figure below, triangles , A, B, C, and  X, Y, Z,  are similar, but not congruent; they have the same angle measures, but not the same side lengths.

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Please help me. Noura is redecorating her house. She needs to work out the area of the wall around her triangular window in orde
Vinvika [58]

Answer:

a. 277.3 m²

b. $307.86

Step-by-step explanation:

a. Area of the wall to be painted = area of rectangle - area of triangle

= L × W + ½×a×b×sin θ

L = 17 m

W = 14 m

a = 8.7 m

b = 9.5 m

θ = 72°

Plug in the values into the equation

Area of the wall = (17×14) + (½*8.7×9.5×sin 72)

Area of the wall = 238 + 39.3024105

Area of the wall to paint ≈ 277.3 m²

b. 20 liters of paint of 1 container cost $21.99

If 1 liter of paint covers 1m², therefore,

277.3 m² will need = 277.3 × 1 = 277.3 liters of paint.

20 liters = 1 container of paint

277.3 liters = 277.3/20 = 13.865 ≈ 14 containers

1 container = $21.99

14 containers = 21.99 × 14 = $307.86

8 0
3 years ago
The area of the base of a prism is 55 mm2. The perimeter of the base is 30 mm. The height of the prism is 7 mm. . . What is the
Eddi Din [679]

The solution would be like this for this specific problem:

<span>7 x 30 = 210 </span>

<span>210 + 55(2) = 320   </span>

<span>
</span>

<span> </span><span>T</span><span>he surface area of the prism is 320 mm2.</span>

 

The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

8 0
4 years ago
Sora correctly solved this inequality. Negative 2.1 w greater-than 12.81. w less-than negative 6.1. Which graph matches the ineq
alina1380 [7]

Answer:

Its the third one I think.

Step-by-step explanation:

I worked on it.

7 0
2 years ago
Read 2 more answers
A term may be written in index form to?
Alecsey [184]

Answer:

A.make calculation easier

8 0
3 years ago
An ellipse has vertices at (0, #17) and foci at (0, ±15). Write the equation of the ellipse in standard form. Graph the ellipse.
Lunna [17]

<u>ANSWER</u>

\frac{ {x}^{2} }{ 64 }  +  \frac{ {y}^{2} }{ 289 }  = 1

See attachment for the graph

<u>EXPLANATION</u>

The standard equation of the vertical ellipse with center at the origin is given by

\frac{ {x}^{2} }{ {b}^{2} }  +  \frac{ {y}^{2} }{ {a}^{2} }  = 1

where

{a}^{2}  \:  >  \:  {b}^{2}

The ellipse has its vertices at (0,±17).

This implies that:a=±17 or a²=289

The foci are located at (0,±15).

This implies that:c=±15 or c²=225

We use the following relation to find the value of b²

{a}^{2}  -  {b}^{2}  =  {c}^{2}

\implies \: 289  -  {b}^{2}  =  225

-  {b}^{2}  =  225 - 289

-  {b}^{2}  =  - 64

{b}^{2}  = 64

We substitute into the formula for the standard equation to get:

\frac{ {x}^{2} }{ 64 }  +  \frac{ {y}^{2} }{ 289 }  = 1

4 0
3 years ago
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