Answer:
6
Step-by-step explanation:
Let the two integers be a and b.
The difference of them is 26. Thus:
One of them (let's use a) is 2 more than 5 times the other. Thus:
Substitute:
Combine like terms:
Subtract 2 from both sides:
Divide by 4:
And the second number is:
Add 6 to both sides:
So, our two numbers are 32 and 6
And the smaller integer is 6.
And we're done :)
<h2>Greetings!</h2><h3>First when doing an inequality, if you find it easier to think of the ≤ signs as equal signs it can make it look easier. </h3>
14 = 2t + 18 = 20
<h3>Because we need to isolate the t, we need to subtract 18 from either side:</h3>
14 - 18 ≤ 2t + 18 - 18 < 20 - 18
<h3>Which then simplifies to:</h3>
-4 ≤ 2t < 2
<h3>Now, to get the t without two lots of it, we simply divide all sides by two:</h3>
-2 ≤ t < 1
<h3>So this means that t is smaller than one and bigger than or equal to -2, and the graph that shows that is C, because it includes -2 but is less than 1.</h3>
<h2>Hope this helps!</h2>
Answer:
81%.
Step-by-step explanation:
To find the average attendance, you will need to find the the total of the average attendance from all 10 days.
Since we know the average attendance of the first 4 meetings was 75%, we can simply assume that those 4 days had this attendance. For this, you can do:
4×75= 300.
Now, for the remaining 6 days, you will need to multiply 85% by the amount of days. 6×85= 510.
Now, to find the average, we will need to add these together:
300+510= 810...
Then divide the result from the total number days to find the AVERAGE:
810÷10= 81%.
Answer:
angle a is 73 and angle c is 180-(73+73)=34
A24 = 141,
using equation,
an = a1 + (n-1)d,
a8 = a + 7d = 45
a16 = a + 15d = 93
solve simultaneously for values a and d, where a = 3, and d = 6.
therefore, inserting values into a24 eqn, where
a24 = 3 + (24-1)(6) = 141.
